Is it possible to configure the async.retry method to retry even upon successful queries, depending on a specific condition?

Question

Is it possible to configure the async.retry method to retry even upon successful queries, depending on a specific condition?

Currently, I am delving into the node.js async module and wondering if it's possible to modify the behavior of the async.retry method. Specifically, I'd like it to retry even on successful operations but halt based on a certain condition or response - for instance, in the case of an API call.

Based on the documentation, this function will keep attempting the task upon failures until it succeeds. Once it does succeed, it will only run that one time. But how can I achieve the same behavior on successful operations and have it stop under a specific condition?

const async = require('async');
const axios = require('axios');

const api = async () => {
    const uri = 'https://jsonplaceholder.typicode.com/todos/1';

    try {
        const results = await axios.get(uri);
        return results.data;
    } catch (error) {
        throw error;
    }
};

const retryPolicy = async (apiMethod) => {
    async.retry({ times: 3, interval: 200 }, apiMethod, function (err, result) {
        // should retry until the condition is met
        if (result.data.userId == 5) {
            // stop retrying
        }
    });
};

retryPolicy(api);

javascript node.js async.js

Answer 1

Answer №1

A solution is to throw a custom error if a certain condition is not met. Your code could look something like this:

const async = require('async');
const axios = require('axios');

const fetchData = async () => {
    const url = 'https://jsonplaceholder.typicode.com/todos/1';

    try {
        const response = await axios.get(url);
        if (response.data.userId != undefined && response.data.userId == 5) { // adjust the condition as needed
            return response.data;
        } else {
            throw { name: "BadDataError", message: "The received data is not valid" };
        }
    } catch (error) {
        throw error;
    }
};

Answer 2

A solution is to throw a custom error if a certain condition is not met. Your code could look something like this:

const async = require('async');
const axios = require('axios');

const fetchData = async () => {
    const url = 'https://jsonplaceholder.typicode.com/todos/1';

    try {
        const response = await axios.get(url);
        if (response.data.userId != undefined && response.data.userId == 5) { // adjust the condition as needed
            return response.data;
        } else {
            throw { name: "BadDataError", message: "The received data is not valid" };
        }
    } catch (error) {
        throw error;
    }
};

Answer 3

Answer №2

It doesn't seem likely that this can be achieved. Check out the description provided on the async.retry documentation page:

This function attempts to execute a task successfully no more than a specific number of times before giving up and returning an error. If the task is successful, the callback function will receive the result. In case all attempts fail, the callback function will receive the error along with the result (if applicable) from the final attempt.

Alternatively, by utilizing the delay function as demonstrated in this example, you can achieve your desired outcome another way:

const async = require('async');
const axios = require('axios');

const delay = (t, val) => {
   return new Promise((resolve) => {
       setTimeout(() => { resolve(val) }, t);
   });
}

const api = async () => {
    const uri = 'https://jsonplaceholder.typicode.com/todos/1';

    try {
        const results = await axios.get(uri);
        return results.data;
    } catch (error) {
        throw error;
    }
};

const retryPolicy = async (apiMethod) => {
    const times = 3
    const interval = 200
    let data

    for (count = 0; count < 3; count++) {
        try {
            data = await apiMethod()
        catch(e) {
            console.log(e)
            await delay(interval)
            continue
        }
        if (data.userId === 5) {
            break;
        }

        await delay(interval)
    }
   
    // carry out further actions
};

retryPolicy(api);

Answer 4

It doesn't seem likely that this can be achieved. Check out the description provided on the async.retry documentation page:

This function attempts to execute a task successfully no more than a specific number of times before giving up and returning an error. If the task is successful, the callback function will receive the result. In case all attempts fail, the callback function will receive the error along with the result (if applicable) from the final attempt.

Alternatively, by utilizing the delay function as demonstrated in this example, you can achieve your desired outcome another way:

const async = require('async');
const axios = require('axios');

const delay = (t, val) => {
   return new Promise((resolve) => {
       setTimeout(() => { resolve(val) }, t);
   });
}

const api = async () => {
    const uri = 'https://jsonplaceholder.typicode.com/todos/1';

    try {
        const results = await axios.get(uri);
        return results.data;
    } catch (error) {
        throw error;
    }
};

const retryPolicy = async (apiMethod) => {
    const times = 3
    const interval = 200
    let data

    for (count = 0; count < 3; count++) {
        try {
            data = await apiMethod()
        catch(e) {
            console.log(e)
            await delay(interval)
            continue
        }
        if (data.userId === 5) {
            break;
        }

        await delay(interval)
    }
   
    // carry out further actions
};

retryPolicy(api);

Is it possible to configure the async.retry method to retry even upon successful queries, depending on a specific condition?

Answer №1

Answer №2

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