Is it possible to avoid passing each individual Vue prop by destructuring them?

Essentially, I am working with a component

<Device>
v-for="device in devices" 
:key="device.name"
:device="device"
:name="device.name"
:number="device.number"
:type="device.type"
:status="device.status"
:plan="device.plan"
:plan_price="device.plan_price"
:health="device.health"
</Device>

Next, I set them up in the props section of the component

props: {
        type: { type: String, default: "" },
        number: { type: String, default: "" },
        name: { type: String, default: ""},
        plan: { type: String, default: "" },
        plan_price: { type: String, default: "" },
        status: { type: Number, default: 0 },
        health: { type: Number, default: 0 },
    },

I'm curious if there's a way to pass :device="device" without needing to individually pass each property. I also aim to avoid using device.name and device.property in the template within the component. Thank you for any advice!

javascriptvue.js

Answer №1

If you utilize v-bind, you can implement a form of object destructuring for props.

<Device>
  v-for="device in devices" 
  :key="device.id"
  v-bind="device"
</Device>

props: {
  type: { type: String, default: "" },
  number: { type: String, default: "" },
  name: { type: String, default: ""},
  plan: { type: String, default: "" },
  plan_price: { type: String, default: "" },
  status: { type: Number, default: 0 },
  health: { type: Number, default: 0 },
}

Check out the demo here: https://stackblitz.com/edit/vue-jngtah?file=src/App.vue

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