I am dealing with an array that contains 3 subarrays.
Arr = [[arr1],[arr2],[arr3]]
My task is to identify and store the duplicate values found in these subarrays ([arr1],[arr2],[arr3]) into a separate array.
Arr2 = [ Duplicate values of arr 1,2,,3 ]
What would be the most effective way to accomplish this using JavaScript?
This code snippet offers a unique approach to solving the given problem.
const data = [
[1,1,2,1,3],
[2,1,4,4,5],
[3,1,4,5,1]
];
// Flattening the two-dimensional array into a single dimension
const transformedArray = data.flat();
const uniqueValuesArray = [];
const duplicateCounts = [];
// Create an array with only unique values
transformedArray.forEach(item => {
if(!uniqueValuesArray.includes(item)) {
uniqueValuesArray.push(item);
}
});
// Count the occurrences of each unique element
uniqueValuesArray.forEach(uItem => {
const count = transformedArray.filter(tItem => tItem === uItem).length;
duplicateCounts.push({
element: uItem,
count: count
});
});
// Testing the output
console.log(transformedArray);
console.log(duplicateCounts);
Initially, my plan was to combine the arrays into a single large array, but it seems like you are interested in finding duplicates that exist in all arrays:
var arr1 = [1, 2, 3, 4]
var arr2 = [1, 2, 4, 8]
var arr3 = [2, 4, 6, 8]
var duplicates = [];
arr1.forEach(function(item) {
// You can switch && to || if needed
if ((arr2.indexOf(item) > -1) && (arr3.indexOf(item) > -1)) {
duplicates.push(item)
}
})
console.log("" + duplicates)Here is a straightforward solution to your query:
const arrayOne = [3, 7, 9, 11];
const arrayTwo = [1, 4, 5, 7];
const arrayThree = [2, 7, 13];
const commonElements = arrayOne.filter((num) => arrayTwo.includes(num) && arrayThree.includes(num));
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