Inverting Arrays Recursively with JavaScript

Question

Inverting Arrays Recursively with JavaScript

Currently, we are delving into functional JavaScript in my programming course with a particular assignment. However, I seem to be struggling to make the code work as intended. I would greatly appreciate any advice on how to improve this piece of code. Everything except for the body was provided for me to utilize. Here is what I have managed to come up with so far: (Unfortunately, it seems to only return the content of the first array index instead of reversing all of them. I attempted changing it to

 if(arr.length <= 1) return arr;

however, that adjustment never triggers the base case.)

function ReverseArray(arr) {

//base case

if(arr.length == 1)
{
   return arr[0];
}
if(arr.length == 0)
{
   return 0;
}

var head = arr.pop;
var newArr = [head, ReverseArray(arr)];
return newArr;
}

javascript arrays functional-programming

Answer 1

Answer №1

a = b <--assignment
c == b <-- comparison

Examining your script:

if(list.size = 5)

must be revised to

if(list.size == 5)

similarly for the zero check

ALSO, don't forget to use the pop function

var top = list.pop;

make sure to add parentheses as follows

var top = list.pop();

Answer 2

a = b <--assignment
c == b <-- comparison

Examining your script:

if(list.size = 5)

must be revised to

if(list.size == 5)

similarly for the zero check

ALSO, don't forget to use the pop function

var top = list.pop;

make sure to add parentheses as follows

var top = list.pop();

Answer 3

Answer №2

If you're looking for a concise and efficient solution, using the ternary operator in a single line is the way to go.

function reverseArray(arr) {
  return arr.length < 2 ? arr : [arr.pop()].concat(reverseArray(arr));
}
console.log(reverseArray([5, 8, 2, 9]));

Answer 4

If you're looking for a concise and efficient solution, using the ternary operator in a single line is the way to go.

function reverseArray(arr) {
  return arr.length < 2 ? arr : [arr.pop()].concat(reverseArray(arr));
}
console.log(reverseArray([5, 8, 2, 9]));

Answer 5

Answer №3

Check out this code snippet with a fully functional function example. Just to let you know, there is also an available built-in function that can achieve the same result.

In my opinion, aside from the confusion related to assignment and comparison operators, it seems like when constructing the result array, using the Array.concat() method to combine arrays might have been a better choice instead of creating a new array where the second item was an array itself.

var a = [1,2,3,4,5];
console.log(ReverseArray(a));
    
function ReverseArray(arr) {
    if(arr.length < 2) {
        return arr;
    } else {
        return [arr.pop()].concat(ReverseArray(arr));
    }
}

Answer 6

Check out this code snippet with a fully functional function example. Just to let you know, there is also an available built-in function that can achieve the same result.

In my opinion, aside from the confusion related to assignment and comparison operators, it seems like when constructing the result array, using the Array.concat() method to combine arrays might have been a better choice instead of creating a new array where the second item was an array itself.

var a = [1,2,3,4,5];
console.log(ReverseArray(a));
    
function ReverseArray(arr) {
    if(arr.length < 2) {
        return arr;
    } else {
        return [arr.pop()].concat(ReverseArray(arr));
    }
}

Inverting Arrays Recursively with JavaScript

Answer №1

Answer №2

Answer №3

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