Instructions for including a sentence in an array as a single element with the split method

Question

Instructions for including a sentence in an array as a single element with the split method

I have a string and I want to turn it into an array by splitting it into individual elements. For example:

let str = "add 2017-04-25 2 USD Jogurt"
str.split(" ");
["add", "2017-04-25", "2", "USD", "Jogurt"]

But how can I combine two words into one element to achieve this format?

add 2017-04-25 3 EUR “French fries”
["add", "2017-04-25", "3", "EUR", "French fries"]

I have heard that regular expressions can be used for this purpose, but I am not sure how to implement it. Perhaps by splitting with another delimiter in the command: add 2017-04-25 3 EUR “French fries”

javascript arrays split

Answer 1

Answer №1

If you frequently encounter expression templates that follow the pattern "ACTION DATE QUANTITY CURRENCY_IN_ISO_4217_FORMAT ITEM_NAME", then utilizing regex can be quite helpful:

"purchase 2020-12-15 5 GBP Laptop".replace(/([A-Z]{3}\s)(.*)$/, '$1"Sunglasses"')

Answer 2

If you frequently encounter expression templates that follow the pattern "ACTION DATE QUANTITY CURRENCY_IN_ISO_4217_FORMAT ITEM_NAME", then utilizing regex can be quite helpful:

"purchase 2020-12-15 5 GBP Laptop".replace(/([A-Z]{3}\s)(.*)$/, '$1"Sunglasses"')

Answer 3

Answer №2

Why not experiment with this...

let txt = "purchase ;2021-09-10 ;5 ;USD ;Burger";
let expression = /\s*(?:;|$)\s*/;
let list = txt.split(expression);
console.log(list[4]);

Answer 4

Why not experiment with this...

let txt = "purchase ;2021-09-10 ;5 ;USD ;Burger";
let expression = /\s*(?:;|$)\s*/;
let list = txt.split(expression);
console.log(list[4]);

Answer 5

Answer №3

If you prefer using a custom function instead of regex, the following code has not been tested for performance against regex.

Input string: 'add 2017-04-25 3 EUR "French crispy fries" and "tasty burger"

Output array: ["add", "2017-04-25", "3", "EUR", "French crispy fries", "and", "tasty burger"]


function myFunction() {
  var str = 'add 2017-04-25 3 EUR "French crispy fries" and "tasty burger"';
  var result = str.split(" ");
  var resultString = [];
  var quotedString = [];
  var ignoreSplit = '"';
  push = 0;
  for(var i=0;i<result.length;i++)
  {
    //start pushing if you found double quotes on starting
    if(result[i].indexOf(ignoreSplit)==0)
    {
            push = 1;
            //replace double quotes to nothing and push
            quotedString.push(result[i].replace(ignoreSplit,''));
    }
    //push if double quotes found in end
    else if(result[i].indexOf(ignoreSplit)>0)
    {
        //stop the push in between
        push = 0;
        quotedString.push(result[i].replace(ignoreSplit,''));
        //push the quoted string in main result string
        resultString.push(quotedString.join(' '));
        //empty quoted string to be used again
        quotedString = [];
    }
    //push if between the double quotes area
    else if(push == 1)
    {
        quotedString.push(result[i]);   
    }
    //push in the main result string normal case
    else
    {
        resultString.push(result[i]);
    }
  }     
   console.log('final ',resultString);
}

Answer 6

If you prefer using a custom function instead of regex, the following code has not been tested for performance against regex.

Input string: 'add 2017-04-25 3 EUR "French crispy fries" and "tasty burger"

Output array: ["add", "2017-04-25", "3", "EUR", "French crispy fries", "and", "tasty burger"]


function myFunction() {
  var str = 'add 2017-04-25 3 EUR "French crispy fries" and "tasty burger"';
  var result = str.split(" ");
  var resultString = [];
  var quotedString = [];
  var ignoreSplit = '"';
  push = 0;
  for(var i=0;i<result.length;i++)
  {
    //start pushing if you found double quotes on starting
    if(result[i].indexOf(ignoreSplit)==0)
    {
            push = 1;
            //replace double quotes to nothing and push
            quotedString.push(result[i].replace(ignoreSplit,''));
    }
    //push if double quotes found in end
    else if(result[i].indexOf(ignoreSplit)>0)
    {
        //stop the push in between
        push = 0;
        quotedString.push(result[i].replace(ignoreSplit,''));
        //push the quoted string in main result string
        resultString.push(quotedString.join(' '));
        //empty quoted string to be used again
        quotedString = [];
    }
    //push if between the double quotes area
    else if(push == 1)
    {
        quotedString.push(result[i]);   
    }
    //push in the main result string normal case
    else
    {
        resultString.push(result[i]);
    }
  }     
   console.log('final ',resultString);
}

Answer 7

Answer №4

Instead of utilizing the split function, you can also opt for using match to locate either the text enclosed in double quotes or match any non-whitespace characters using an alternation.

Remember to include the global flag /g to match all instances.

/(?<=“)[^“”]*(?=”)|[^\s“”]+/g

Explanation

(?<=“) Positive lookbehind to confirm the presence of “
[^“”]* Matches zero or more characters that are not “ or ”
(?=”) Positive lookahead to confirm the existence of ”
| Or
[^\s“”]+ Matches one or more characters that are not “, ”, or whitespace

Check out the Regex demo

[
  "add 2017-04-25 2 USD Yogurt",
  "add 2017-04-25 3 EUR “French fries”"
].forEach(s => console.log(s.match(/(?<=“)[^“”]*(?=”)|[^\s“”]+/g)));

Answer 8

Instead of utilizing the split function, you can also opt for using match to locate either the text enclosed in double quotes or match any non-whitespace characters using an alternation.

Remember to include the global flag /g to match all instances.

/(?<=“)[^“”]*(?=”)|[^\s“”]+/g

Explanation

(?<=“) Positive lookbehind to confirm the presence of “
[^“”]* Matches zero or more characters that are not “ or ”
(?=”) Positive lookahead to confirm the existence of ”
| Or
[^\s“”]+ Matches one or more characters that are not “, ”, or whitespace

Check out the Regex demo

[
  "add 2017-04-25 2 USD Yogurt",
  "add 2017-04-25 3 EUR “French fries”"
].forEach(s => console.log(s.match(/(?<=“)[^“”]*(?=”)|[^\s“”]+/g)));

Instructions for including a sentence in an array as a single element with the split method

Answer №1

Answer №2

Answer №3

Answer №4

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