Instructions for appending additional values from two arrays to the end of a newly created array

Question

Instructions for appending additional values from two arrays to the end of a newly created array

Suppose I have 2 arrays as follows: let array1 = [1,2,3]; and let array2 = [5,6,7,8,9]. How can I generate a new third array that specifically includes the elements from array2 located at the additional indexes (meaning the new array would exclusively have [8,9] since they are found at index 3 and 4).

Your help is much appreciated!

javascript arrays concatenation push mutation

Answer 1

Answer №1

A helpful tool in Javascript is the slice() function.

array1 = [10,20,30]
array2=[50,60,70,80,90]

array3 = array2.slice(array1.length , array2.length)

console.log(array3)

Answer 2

A helpful tool in Javascript is the slice() function.

array1 = [10,20,30]
array2=[50,60,70,80,90]

array3 = array2.slice(array1.length , array2.length)

console.log(array3)

Answer 3

Answer №2

If you're looking for a solution, one approach involves using the slice method with a negative index. Specifically, the negative index can be calculated as

(array2.length - array1.length) * -1

.

const array1 = [1, 2, 3],
  array2 = [5, 6, 7, 8, 9],
  sliceArray = (a1, a2) => a2.length <= a1.length ? [] : a2.slice((a2.length - a1.length) * -1)


console.log(sliceArray([], [])); // expected output: []
console.log(sliceArray([1, 3, 6], [1, 2])); // expected output: []
console.log(sliceArray(array1, array2)); // expected output: [8, 9]

Answer 4

If you're looking for a solution, one approach involves using the slice method with a negative index. Specifically, the negative index can be calculated as

(array2.length - array1.length) * -1

.

const array1 = [1, 2, 3],
  array2 = [5, 6, 7, 8, 9],
  sliceArray = (a1, a2) => a2.length <= a1.length ? [] : a2.slice((a2.length - a1.length) * -1)


console.log(sliceArray([], [])); // expected output: []
console.log(sliceArray([1, 3, 6], [1, 2])); // expected output: []
console.log(sliceArray(array1, array2)); // expected output: [8, 9]

Answer 5

Answer №3

const firstArray = [2, 4, 6, 8, 10];
const secondArray = [3, 6, 9];
const newArray = firstArray.length > secondArray.length ? firstArray.slice(secondArray.length, firstArray.length) : secondArray.slice(firstArray.length, secondArray.length);
console.log(newArray);

Implementing ternary operator and slice method

Answer 6

const firstArray = [2, 4, 6, 8, 10];
const secondArray = [3, 6, 9];
const newArray = firstArray.length > secondArray.length ? firstArray.slice(secondArray.length, firstArray.length) : secondArray.slice(firstArray.length, secondArray.length);
console.log(newArray);

Implementing ternary operator and slice method

Answer 7

Answer №4

If you want a simple way to find the longer array and slice it, you can use this handy function. With this method, there's no need to worry about which array is longer beforehand:

function getLongerArray (array1, array2) {
  if (array1.length === array2.length) return [];

  const [shortArray, longArray] = [array1, array2]
    .sort((a, b) => a.length - b.length);

  return longArray.slice(shortArray.length);
}

const numbers1 = [1,2,3];
const numbers2 = [5,6,7,8,9];

const result = getLongerArray(numbers1, numbers2);
console.log(result); // [8, 9]

const result2 = getLongerArray(numbers2, numbers1);
console.log(result2); // [8, 9]

Answer 8

If you want a simple way to find the longer array and slice it, you can use this handy function. With this method, there's no need to worry about which array is longer beforehand:

function getLongerArray (array1, array2) {
  if (array1.length === array2.length) return [];

  const [shortArray, longArray] = [array1, array2]
    .sort((a, b) => a.length - b.length);

  return longArray.slice(shortArray.length);
}

const numbers1 = [1,2,3];
const numbers2 = [5,6,7,8,9];

const result = getLongerArray(numbers1, numbers2);
console.log(result); // [8, 9]

const result2 = getLongerArray(numbers2, numbers1);
console.log(result2); // [8, 9]

Instructions for appending additional values from two arrays to the end of a newly created array

Answer №1

Answer №2

Answer №3

Answer №4

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