var arr=[1,2,3,[4,5],6,[7,8,9]],x,j;
for(x in arr)
for(j in arr[x])
console.log(arr[x][j]);
The desired output should be 1, 2, 3,..., 9. However, the current code generates 4, 5, 7, 8, 9.
var arr=[1,2,3,[4,5],6,[7,8,9]],x,j;
for(x in arr)
for(j in arr[x])
console.log(arr[x][j]);
The desired output should be 1, 2, 3,..., 9. However, the current code generates 4, 5, 7, 8, 9.
In my opinion, simply using the "join" method should suffice:
var result = arr.join();
console.log(result);
If I have correctly understood your inquiry, you are seeking to console log numbers 1 through 9. The current setup will only output the arrays within your array, explaining why you are receiving 4, 5, 7, 8, and 9.
One approach is to verify if the value is an array in your initial loop - if it is, iterate through it and display the values. If not, simply print the value.
if(arr[x].constructor === Array) {
//loop over the array and print out the values
for (j in arr[x]) {
console.log(arr[x][j])
}
} else {
//print out the plain value
console.log(arr[x])
}
You can view the results in this codepen: http://codepen.io/kyledodge/pen/zGwPBo
Alternatively, recursion can be used. A sample implementation could look like this:
var printArrayValue = function(array) {
for (var i = 0; i < array.length; i++) {
if (array[i].constructor === Array) {
//if this an array, call this function again with the value
printArrayValue(array[i]);
} else {
//print the value
console.log(array[i]);
}
}
}
printArrayValue(arr);
View the outcome in this codepen: http://codepen.io/kyledodge/pen/VLbrPX
Convert each element into an array:
let myArray = [10, 20, 30, [40, 50], 60, [70, 80, 90]], index;
for(index in myArray) {
let newArray = [].concat(myArray[index]);
^^^^^^^^^^^^^^^^^
for(let j in newArray)
console.log(newArray[j]);
}
This method is effective because concat can handle both arrays and single values.
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