Indicate the end of the row in JavaScript when using the match() function

Question

Indicate the end of the row in JavaScript when using the match() function

What's the best way to identify the end of a row when using the match() function? I'm trying to extract "2021 JANUARY 18 MONDAY" from this page.

https://i.sstatic.net/bTNdQ.png

https://i.sstatic.net/YzFs2.png

If there is additional text after the desired string, I typically use this code:

var content = UrlFetchApp.fetch(url).getContentText();

var date = content.match(/results of (.*?)SOMETHING/m)[1];

However, I am currently facing some difficulties with this method.

javascript string match

Answer 1

Answer №1

This is a simple example demonstrating how to match a specific date format within a string:

let text = "lorem ipsum 2021 January 18 Monday";
let matchingDate = text.match(/(\d{4} [A-z]+ \d{1,2} [A-z]+)/)[0] || null;

console.log(matchingDate);

Answer 2

This is a simple example demonstrating how to match a specific date format within a string:

let text = "lorem ipsum 2021 January 18 Monday";
let matchingDate = text.match(/(\d{4} [A-z]+ \d{1,2} [A-z]+)/)[0] || null;

console.log(matchingDate);

Answer 3

Answer №2

If you want to ensure the date at the end of the row matches, consider using the anchor character "$" and refining the format for the date pattern.

It's important to note that the regular expression [A-z] actually matches more than [A-Za-z]. To make the pattern case insensitive, you can include the flag /i.

^.* ((?:19|20)\d{2} [A-Z]+ (?:0?[1-9]|[12]\d|3[01]) [A-Z]+)$

Check out a demo of this regex here.

^ Denotes the start of the string
.* Matches any character 0 or more times until the last space
( Captures group 1 which contains the date value
- (?:19|20)\d{2} Matches a year starting with 19 or 20 followed by 2 digits and a space
- [A-Z]+ Matches one or more uppercase letters A-Z followed by a space
- (?:0?[1-9]|[12]\d|3[01]) Matches a day from 1 to 31
- [A-Z]+ Matches one or more uppercase letters A-Z followed by a space
) Closes group 1
$ Denotes the end of the string

var page = "NHL 2020-2021 ratings through results of 2021 JANUARY 18 MONDAY";
var date = page.match(/^.* ((?:19|20)\d{2} [A-Z]+ (?:0?[1-9]|[12]\d|3[01]) [A-Z]+$)/i)
if (date)
  console.log(date[1]);

Answer 4

If you want to ensure the date at the end of the row matches, consider using the anchor character "$" and refining the format for the date pattern.

It's important to note that the regular expression [A-z] actually matches more than [A-Za-z]. To make the pattern case insensitive, you can include the flag /i.

^.* ((?:19|20)\d{2} [A-Z]+ (?:0?[1-9]|[12]\d|3[01]) [A-Z]+)$

Check out a demo of this regex here.

^ Denotes the start of the string
.* Matches any character 0 or more times until the last space
( Captures group 1 which contains the date value
- (?:19|20)\d{2} Matches a year starting with 19 or 20 followed by 2 digits and a space
- [A-Z]+ Matches one or more uppercase letters A-Z followed by a space
- (?:0?[1-9]|[12]\d|3[01]) Matches a day from 1 to 31
- [A-Z]+ Matches one or more uppercase letters A-Z followed by a space
) Closes group 1
$ Denotes the end of the string

var page = "NHL 2020-2021 ratings through results of 2021 JANUARY 18 MONDAY";
var date = page.match(/^.* ((?:19|20)\d{2} [A-Z]+ (?:0?[1-9]|[12]\d|3[01]) [A-Z]+$)/i)
if (date)
  console.log(date[1]);

Indicate the end of the row in JavaScript when using the match() function

Answer №1

Answer №2

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