Increase the day count by 1 on every third cycle

Question

Increase the day count by 1 on every third cycle

I've been working on a code to increment the days in a date variable every third iteration using modulus.

While I have managed to get the logic for every third iteration right, the day doesn't seem to increase by 1. I searched online and found suggestions to use

date.setDate(date.getDate() + 1);

, which I incorporated into my code. However, it only increments once and then remains stagnant.

Below is the code snippet of what I have experimented with:

for (let i = 0; i < 10; i++) {
                let date = new Date();
                if (i % 3 == 0) {
                    date.setDate(date.getDate() + 1);
                    console.log(date);
                }
            }

javascript date

Answer 1

Answer №1

If you want to achieve your desired outcome, it's advisable to move the date variable outside of the loop. The code snippet below illustrates how this can be done, along with explanations on why it is necessary:

/* 
By moving "date" outside of the loop, you establish a fixed reference point
for incrementing during each iteration 
*/
let date = new Date();

for (let i = 0; i < 10; i++) {
 
  if (i % 3 == 0) {

    /*
    Increment the day of the date object that remains outside the loop.
    Since the date object is defined externally, these increments are retained
    across iterations of the loop
    */
    date.setDate(date.getDate() + 1);
    console.log(date);
  }
}

Answer 2

If you want to achieve your desired outcome, it's advisable to move the date variable outside of the loop. The code snippet below illustrates how this can be done, along with explanations on why it is necessary:

/* 
By moving "date" outside of the loop, you establish a fixed reference point
for incrementing during each iteration 
*/
let date = new Date();

for (let i = 0; i < 10; i++) {
 
  if (i % 3 == 0) {

    /*
    Increment the day of the date object that remains outside the loop.
    Since the date object is defined externally, these increments are retained
    across iterations of the loop
    */
    date.setDate(date.getDate() + 1);
    console.log(date);
  }
}

Answer 3

Answer №2

The issue lies in the fact that a new instance of the Date object is being created during each iteration of the loop. To resolve this, simply declare the variable date outside of the loop, as shown below:

let date = new Date();

for (let i = 0; i < 10; i++) {
  if (i % 3 == 0) {
    date.setDate(date.getDate() + 1);
    console.log(date);
  }
}

Answer 4

The issue lies in the fact that a new instance of the Date object is being created during each iteration of the loop. To resolve this, simply declare the variable date outside of the loop, as shown below:

let date = new Date();

for (let i = 0; i < 10; i++) {
  if (i % 3 == 0) {
    date.setDate(date.getDate() + 1);
    console.log(date);
  }
}

Answer 5

Answer №3

Make sure to declare the date variable outside of the loop to avoid resetting it unnecessarily.

let currentDate = new Date();
for (let j = 0; j < 4; j++) {
  if (j % 2 == 0) {
    currentDate.setDate(currentDate.getDate() + 1);
    console.log(currentDate);
  }
}

Answer 6

Make sure to declare the date variable outside of the loop to avoid resetting it unnecessarily.

let currentDate = new Date();
for (let j = 0; j < 4; j++) {
  if (j % 2 == 0) {
    currentDate.setDate(currentDate.getDate() + 1);
    console.log(currentDate);
  }
}

Answer 7

Answer №4

It's important to move the definition of your date variable outside of the loop to optimize performance.

let date = new Date();

for (let i = 0; i < 10; i++) {
  if (i % 3 == 0) {
    date.setDate(date.getDate() + 1);
    console.log(i, date);
  }
}

Answer 8

It's important to move the definition of your date variable outside of the loop to optimize performance.

let date = new Date();

for (let i = 0; i < 10; i++) {
  if (i % 3 == 0) {
    date.setDate(date.getDate() + 1);
    console.log(i, date);
  }
}

Increase the day count by 1 on every third cycle

Answer №1

Answer №2

Answer №3

Answer №4

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