Is it possible to output the result from the 'three' function to console.log in the 'one' function?
one = async (number) => {
console.log(`we received ${number}`)
await two(number)
console.log('the number three should be displayed here')
}
two = async (number) => {
number++
console.log(`I obtained ${number}`)
await three(number)
}
three = (number) => {
number++
console.log(`final step is ${number}`)
}
one(1)
The connected functions are intended to yield an increased number. It's worth noting that as two promptly returns the result of calling three, it doesn't need to be marked as async. You can simply change it into a regular function that delivers three's Promise:
one = async (number) => {
console.log(`we received ${number}`)
const resTwo = await two(number)
console.log('the number three should be here ' + resTwo)
}
two = (number) => {
number++
console.log(`I got ${number}`)
return three(number)
}
three = (number) => {
number++
console.log(`last but not least ${number}`)
return number;
}
one(1)let count = 0;
async function returnNumber() {
return Promise.resolve(count++);
}
returnNumber(count).then(alert); // 0
returnNumber(count).then(alert); // 1
returnNumber(count).then(alert); // 2
returnNumber(count).then(alert); // 3We can use a promise to explicitly return a value
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