Can you explain why console.log(a) and console.log(b) do not return the same result of [1, 2, 3, 4]?
function test(c, d) {
c = [1, 2, 3, 4];
d.push(4);
}
a = [1, 2, 3];
b = [1, 2, 3];
test(a, b);
console.log(a);
console.log(b);
Can you explain why console.log(a) and console.log(b) do not return the same result of [1, 2, 3, 4]?
function test(c, d) {
c = [1, 2, 3, 4];
d.push(4);
}
a = [1, 2, 3];
b = [1, 2, 3];
test(a, b);
console.log(a);
console.log(b);
By initializing a = [1, 2, 3, 4];, you are essentially reassigning the argument (local to the function) passed into the test function. This does not modify the original array a. As a result, the a inside now references a different array than the one outside.
However, when b.push(4) is executed, it directly alters the external b array.
function test(a, b) {
a = [1, 2, 3, 4];
b.push(4);
}
a = [1, 2, 3];
b = [1, 2, 3];
test(a, b);
console.log(a);
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