In need of assistance, please. I have two arrays apple = [1,5,10,15,20], bottle = [1,5,10,15,20,25]. Using either lodash or any JavaScript function, I am attempting to create a new array called 'c' that contains only unique elements such as c= [25]. Essentially, I want to compare the 'apple' array with the 'bottle' array and then display all the elements that are unique.
One approach is to utilize Array#filter in conjunction with a Set representing the opposite array.
This method employs a complement function, returning true if element a is not present in set b.
In order to achieve a symmetric difference, filtering with callback functions must be applied on both ends.
function getComplement(collection) {
// Initialize and retain a set generated from the provided collection
var set = new Set(collection);
// Define an iterator callback for .filter()
return function (item) {
return !set.has(item);
};
}
var apple = [1,5,10,15,20],
bottle = [1,5,10,15,20,25],
unique = [
...apple.filter(getComplement(bottle)),
...bottle.filter(getComplement(apple))
];
console.log(unique);You have the ability to craft your own function using reduce() and filter() to achieve this task.
var apple = [1,5,10,15,20], bottle = [1,5,10,15,20,25]
function findUniqueElements(arr1, arr2) {
var mergedArray = arr1.concat(arr2);
var countObj = mergedArray.reduce(function(result, element) {
result[element] = (result[element] || 0) + 1;
return result;
}, {});
return Object.keys(countObj).filter(function(element) {
return countObj[element] == 1;
});
}
console.log(findUniqueElements(apple, bottle))A more concise version of the same code using ES6 arrow functions.
var apple = [1,5,10,15,20], bottle = [1,5,10,15,20,25]
function findUniqueElements(arr1, arr2) {
var countObj = arr1.concat(arr2).reduce((r, e) => (r[e] = (r[e] || 0) + 1, r), {});
return Object.keys(countObj).filter(e => countObj[e] == 1);
}
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