The display option is not required in the function, but I am confused about its usage with || true
Which part of the code actually evaluates this condition? if(display || true){...}
if(display || true){
$("#container").fillContent(this.showReport(this.tabData, additionalInfo || false));
}
The || operator performs a logical or operation, resulting in true if either operand is true.
In this case, your code can be simplified to just {...}, as the conditional statement is unnecessary given that it will always evaluate to true.
if(display || true)
This specific if statement is used to determine the truth value of the variable display. If the variable is evaluated as true, then the entire conditional expression automatically becomes true. On the other hand, if the display variable is false, the program moves on to evaluate the second condition.
An 'or' condition requires only one of the expressions to be true in order for the overall statement to be deemed true.
In this scenario, due to the presence of a true statement in the 'or' condition, the code will consistently yield a true result.
experiment with a modification,
if(condition || true){
$("#element").html(this.updateContent(this.data, additionalData || false));
}
adjust it to
if(true){
$("#element").html(this.updateContent(this.data, additionalData || false));
}
This code snippet demonstrates an incorrect usage of the || operator as a coalescing operator. As previously mentioned, it will always result in true. However, consider a scenario where display is a string instead of a boolean.
var result = display || "(none)";
In this case, the above line of code will return either the value of display, or if display is not set, it will return "(none)".
This behavior leverages the fact that in JavaScript, both undefined and null are evaluated as false. Therefore, when a value is not assigned, using || allows for the fallback value to be returned - since the left operand is false, the evaluation results in the right value being returned, regardless of its content.
The individual who wrote this code snippet likely copied it from legacy code or a JavaScript resource without fully grasping the underlying mechanics and limitations. It's essential to understand that values like false and 0 are also treated as falsy in JavaScript, leading to the unexpected outcome of always receiving true in your specific case.
It's important to note that extraInfo || false does function as intended. The issue lies specifically with the true part causing the problem. To rectify this, you can simply utilize:
if (!(display === false))
By employing a type-sensitive comparison here, if display is undefined, it will evaluate to false, providing the default true. Conversely, if display is explicitly set to true, it will return true; and if display is set to false, it will result in !true, which is false.
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