In JavaScript, use a regular expression to replace all instances of %2F with %

Looking for a JavaScript/regex solution to transform %2F into %21.

This will allow me to successfully pass forward slashes through a GET parameter after using encodeURIComponent() on a URL.

Once the data reaches the server, I'll convert back from ! to /.

Although not perfect, this workaround is necessary due to limitations with my rewrite rules.

Answer №1

After spending quite some time researching, I was able to find a solution to the problem at hand despite not being as skilled as others in this community. Regardless, I wanted to share my findings.

The issue arises from the server prematurely decoding %2F, resulting in an incorrect path.

To fix this, you need to replace %2F with %252F on the client side.

x = x.replace(/%2F/gi, "%252F");

This double encoded form ensures that when the data reaches the server, it is decoded correctly as %2F instead of misinterpreting it as something else.

I hope this explanation helps!

Answer №2

Have you attempted using the String.replace method?

let x = x.replace(/%2F/gi, "%21");

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