In JavaScript, private variables are not included in the JSON.stringify output

Question

In JavaScript, private variables are not included in the JSON.stringify output

Imagine creating a class called Rectangle with private fields like width and height, initializing them in the constructor. However, when calling JSON.stringify on an instance of this class, it returns an empty object without including the private members.

Is there a simpler way to make private fields visible in the JSON output without having to create a toJSON method for each member? It seems tedious to manually include every private field in the toJSON method.

javascript json class private class-fields

Answer 1

Answer №1

Restricted properties can only be accessed within the class itself. To access them, you must create a custom serialization method:

class Square {
  #side;
  constructor() {
    this.#side = 4;
  }

  serialize() {
    return JSON.stringify({['#side']: this.#side})
  }

}

let sq = new Square();

console.log(sq.serialize())

Answer 2

Restricted properties can only be accessed within the class itself. To access them, you must create a custom serialization method:

class Square {
  #side;
  constructor() {
    this.#side = 4;
  }

  serialize() {
    return JSON.stringify({['#side']: this.#side})
  }

}

let sq = new Square();

console.log(sq.serialize())

Answer 3

Answer №2

To simplify the process of specifying all the members individually, one approach is to utilize a solitary private data property within the instance and then handle serialization and deserialization through that property:

class Square {
   #data;
   constructor(data) {
      this.#data = data;
   }
   getSideLength = () => this.#data.sideLength;
   toJson = () => JSON.stringify(this.#data);
}
const s = new Square({ sideLength: 5 });
console.log(s.getSideLength());
const serialized = s.toJson();
console.log(serialized);

const reconstructed = new Square(JSON.parse(serialized));
console.log(reconstructed.getSideLength());

Answer 4

To simplify the process of specifying all the members individually, one approach is to utilize a solitary private data property within the instance and then handle serialization and deserialization through that property:

class Square {
   #data;
   constructor(data) {
      this.#data = data;
   }
   getSideLength = () => this.#data.sideLength;
   toJson = () => JSON.stringify(this.#data);
}
const s = new Square({ sideLength: 5 });
console.log(s.getSideLength());
const serialized = s.toJson();
console.log(serialized);

const reconstructed = new Square(JSON.parse(serialized));
console.log(reconstructed.getSideLength());

Answer 5

Answer №3

Avoid utilizing private variables as they serve no purpose.

Answer 6

Avoid utilizing private variables as they serve no purpose.

In JavaScript, private variables are not included in the JSON.stringify output

Answer №1

Answer №2

Answer №3

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