In JavaScript, create a function that takes a String as input, moves the first letter of each word to the end of that word, appends "ay" to the end, and returns the transformed String

My current progress is:

function pigIt(str) {

  //split the string into an array of words
  let words = str.split(" ");

  //iterate through the array of words
  for (let i = 0; i < words.length; i++) {

    //loop through individual words
    for (let j = 0; j < words.length; j++) {

      //get the first word in the array
      let firstWord = words[0];

      //get the first character in the first word
      let firstChar = firstWord[0];

      //create a new word without the first character
      let unshiftedWord = firstWord.unshift(0);

      //move the first character to the end
      let newWord = unshiftedWord.push(firstChar) + "ay";

      return newWord;

    }
  }
}

console.log(pigIt('Pig latin is cool'));

At this point, my goal is to simply return "igPay". Later on, I will concatenate the strings to form a new one.

However, there's an issue with firstWord.unshift(0);. It's showing the error:

TypeError: firstWord.unshift is not a function.

Even though .unshift() is a function according to MDN documentation, it's not working here. Why might that be?

Once I manage to generate a new word, I can combine the newWords to create a newString. There must be a more efficient way than using separate loops for each word.

EDIT: My intention is to write this function using traditional function declaration, rather than arrow notation.

EDIT 2 With @Ori Drori's solution in place, my updated function looks like:

function pigIt(str) { 

  newString = str.replace(/(\S)(\S+)/g, '$2$1ay');
  return newString;
}

console.log(pigIt('Pig latin is cool'));

Surprisingly, it works - although I'm still puzzled by what

str.replace(/(\S)(\S+)/g, '$2$1ay');
actually accomplishes.

Answer №1

To convert words to pig latin, you can utilize a regular expression (regex101) along with String.replace(). The regex captures the first letter and the remaining letters of each word (a sequence of non-space characters). By using the replacement pattern ($2$1ay), you reconstruct the word in pig latin.

const pigIt = (str) => str.replace(/(\w)(\w+)/g, '$2$1ay')

console.log(pigIt('Pig latin is cool'));

Explanation of the replace method:

  • The regex matches the first character of the word (\w) and stores it as $1
  • The regex captures the remaining characters of the word and stores them as $2
  • The replacement specifies that the new string will be formed by $2 followed by $1 and then "ay"

Note: The use of \S ensures all non-space characters are accounted for.

Answer №2

A more straightforward approach is to use a combination of map() and join().

Note: Based on the Codewars example, only alphabets like ay are added to strings, not symbols like !. It's important to check if the element in the array is an alphabet or not using the test() method.

All the tests on Codewars pass with the following solution:

function pigIt(str){
  return str.split(' ').map(x =>/[a-zA-Z]+/.test(x) ? x.slice(1)+x[0]+'ay' : x).join(' ');
}
console.log(pigIt('Pig latin is cool'));

Using Regular Function instead of Arrow Function

function pigIt(str){
  return str.split(' ').map(function(x){ 
      return /[a-zA-Z]+/.test(x) ? x.slice(1)+x[0]+'ay' : x;
  }).join(' ');
}
console.log(pigIt('Pig latin is cool'));

Implementing with a Simple for Loop

Below is the code using a basic for loop:

function pigIt(str){
  str = str.split(' ');
  for(let i = 0;i<str.length;i++){
    if(/[a-zA-Z]/.test(str[i])){
      str[i] = str[i].slice(1) + str[i][0] + 'ay';
    } 

  }
  return str.join(' ');
}
console.log(pigIt('Pig latin is cool'));

Answer №3

unshift is not a method on a string.

To achieve a similar effect, you can split the string by space, map through the array elements to swap positions and add "ay", then join them back together with a space.

let str = `Pig latin is cool`

let op = str.split(' ').map(e => e.substr(1,) + e[0] + 'ay').join(' ')

console.log(op)

If you prefer to avoid arrow functions, you can achieve the same result using a traditional function declaration within the map method.

let str = `Pig latin is cool`

let op = str.split(' ').map(function(e){
  return e.substr(1,) + e[0] + 'ay'
}).join(' ')

console.log(op)

Answer №4

You should give this a try, it's effective and doesn't require Regex

function convertPigLatin(str){
       let words = str.split(" ");
       let newWords = [];
       for ( let i = 0 ; i < words.length ; i++ ) {
          if ( words[i] === "!" || words[i] === "?" ){
             newWords.push(words[i]);
          } else { 
             let pigLatin = words[i].slice(1) + words[i].charAt(0) + "ay";
             newWords.push(pigLatin)
          }
        }
      return newWords.join(" ")
    } 

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