Ignore non-existent items in React-Native by filtering them out

I'm currently faced with a scenario where I need to loop through an array of objects. Specifically, when there are more than two objects in the array and the first object is missing, how can I skip it and move on to the next one?

Check out the loop below:

 for (i = 0; i < this.myInputFields.myTextFields.length; i++) {

        if (!this.myInputFields.myTextFields[i] || this.myInputFields.myTextFields[i] == null || this.myInputFields.myTextFields[i] === '') {
           // Move to the next object
        }

        if (this.myInputFields.myTextFields[i].key) {
             data[this.myInputFields.myTextFields[i].key] = this.myInputFields.myTextFields[i].inputValues;
        }

    }

Here's the printed array example when the first object is missing:

    [ ,
   { type: 'textfield',
     placeholderText: 'Enter your number',
     title: '*number',
     key: 'signedByNumber',
   inputType: 'numbers',
    inputValues: '553' } ]

If you noticed, before the second object there is a comma followed by a space that I need to skip somehow.

Answer №1

This code snippet enables you to bypass any empty elements within a collection.

for (let i = 0; i < this.myInputFields.myTextFields.length; i += 1) {
  if (this.myInputFields.myTextFields[i]) {
    // Handle valid elements as needed
    data[this.myInputFields.myTextFields[i].key] = this.myInputFields.myTextFields[i].inputValues;
  }
}

An alternative and more efficient approach would be

let array = this.myInputFields.myTextFields.filter(item => item !== undefined); // Use filter method to remove all undefined elements

for (let i = 0; i < array.length; i += 1) {
  data[array[i].key] = array[i].inputValues;
}

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