If the condition has a class name of condition, then display

Having performance issues due to slow data rendering with each tab using a partial view. The code snippet for each tab is as follows:

<div class="tab-content" ng-controller="MyController">
    <div id="tab-1" class="tab-pane fade active in " ng-include="'PartialViews/1.html'"></div>
    <div id="tab-2" class="tab-pane fade" ng-include="'PartialViews/2.html'"></div>                            
    <div id="tab-3" class="tab-pane fade" ng-include="'PartialViews/3.html'"></div>                            
    <div id="tab-4" class="tab-pane fade" ng-include="'PartialViews/4.html'"></div>                        
    <div id="tab-5" class="tab-pane fade" ng-include="'PartialViews/5.html'"></div>  
</div>

A recommendation was made to use ngIf by wrapping the inner content into a separate partial and ngInclude. This approach prevents unnecessary loading and evaluation of partials when the condition is false from the outset.

I want to implement an ng-if condition based on the active tab (the active tab has the class "tab-pane fade active in"). I'm struggling to figure out how to include a class name-based expression inside ngIf. Any assistance would be greatly appreciated.

Answer №1

To avoid conflicts with your #tab-content Controller, consider implementing a scope variable to track the active view. Then, utilize ng-if or ng-switch to selectively include the necessary views.

You can set the model using ng-click (and passing it through a service for navigation under a different controller) or add a routeParameter to update your "activeTab" scope variable accordingly.

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