Identifying iOS 5 or above using JavaScript

I've been experimenting with this code snippet to check if the browser is iOS 5 or newer (found on this Stack Overflow thread Detect iOS version less than 5 with JavaScript).

function iOSversion() {
    if (/iP(hone|od|ad)/.test(navigator.platform)) {
        var v = (navigator.appVersion).match(/OS (\d+)_(\d+)_?(\d+)?/);
        return [parseInt(v[1], 10), parseInt(v[2], 10), parseInt(v[3] || 0, 10)];
    }
}

ver = iOSversion();

if (ver[0] >= 5) {
    alert('This is running iOS 5 or newer.');
} else {
    alert('This is NOT running iOS 5 or newer.');
}

It functions correctly on iOS 5 or above, but triggers the following error in other browsers:

Uncaught TypeError: Cannot read property '0' of undefined

Subsequently, all JavaScript after this specific code fails to execute.

I would appreciate any guidance on resolving this issue. Thank you.

javascriptiosuser-agent

Answer №1

Check if ver[0] is greater than or equal to 5, but remember that if it's not iOS, then ver will be undefined. Make sure to verify its definition before proceeding :

function iOSversion() {
    if (/iP(hone|od|ad)/.test(navigator.platform)) {
        var v = (navigator.appVersion).match(/OS (\d+)_(\d+)_?(\d+)?/);
        return [parseInt(v[1], 10), parseInt(v[2], 10), parseInt(v[3] || 0, 10)];
    }
}

var ver = iOSversion();

if (ver && ver[0] >= 5) {
    alert('This is running iOS 5 or later.');
} else {
    alert('This is NOT running iOS 5 or later.');
}

Answer №2

FunctionToCheckiOSVersion() will only work on iOS devices.

Attempting to access undefined[0] will result in the same error message you encountered.

To avoid this error, update your verification method to:

if (version !== undefined && version[0] >= 5) {
    // ..
}

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