Identifying a Malformed URI in JavaScript

In JavaScript, it is considered a best practice to use certain patterns to detect errors instead of solely relying on try-catch blocks. One easy way to do this is by using TypeError:

if (typeof foo !== "number") {
  console.log("That ain't a number!");
  return;
}

Similar patterns can be used for detecting ReferenceError and RangeError as well.

However, the challenge arises when trying to test for a URIError before utilizing encodeURI() or decodeURI() without resorting to try-catch blocks.

(An acceptable response might be that it is not possible).

Answer №1

Verifying a URI for any potentially harmful escape characters prior to decoding seems to be the most effective approach, wouldn't you agree?

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