Identify unique MongoDb instances within an array of data

My list contains various unique items -

search = alluk.distinct('Object of search')

I am interested in counting each item individually. Presently, I am counting them manually in the following way -

alluk.find({'Object of search':'Offensive weapons'}).count()

Query

Is there a way to iterate through the search array and count each item one by one?

I have attempted the following -

alluk.find({'Object of search':{'$in': search}}).count()

However, this approach does not achieve exactly what I desire.

SOLUTION -

for item in alluk.aggregate([
  { '$match': { 'Object of search': { '$in': objectofsearch }}},
  { '$group': {
    '_id': '$Object of search',
    'count': { '$sum': 1 }
  }}
]):
    print(item)

Answer №1

If you're looking to tally up unique counts, consider using the $group aggregation method.

alluk.aggregate([
  { '$match': { 'Object of search': { '$in': search }}},
  { '$group': {
    '_id': '$Object of search',
    'count': { '$sum': 1 }
  }}
])

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