Identify and handle multiple scenarios in JavaScript without using if statements

I have developed a function that is supposed to evaluate all scenarios and provide an immediate result if one of the cases does not match.

const addText = (data, addAlternative) => {
        return (data !== 'N/T' || data === 0 || data) ? data : addAlternative;
};
console.log(addText('N/T', 'alternative'))

When using addText('N/T', 'alternative'), I am getting N/T instead of the expected result alternative. How can I modify my code to thoroughly check all situations and return the correct answer as shown in the example?

Answer №1

When you see `NT` as the output, it is because of the condition set in the function where data is checked for truthy status using

data !== 'N/T' || data === 0 || data
.

To fix this issue, simply update the condition to data !== 'N/T' || data === 0, and it should work correctly.

const addDefaultTextIfIsEmpty = (data, addAlternative) => {
  return (data !== 'N/T' || data === 0) ? data : addAlternative;
};
console.log(addDefaultTextIfIsEmpty('N/T', 'alternative'))

If you want to display data when the parameter is not defined, you can use !data within the condition. In this case, you don't need to include data === 0. The !data will cover checks for null, undefined, empty, and zero.

const addDefaultTextIfIsEmpty = (data, addAlternative) => {
  return (data !== 'N/T' || !data) ? data : addAlternative;
};
console.log(addDefaultTextIfIsEmpty('N/T', 'alternative'))

Answer №2

In order to avoid testing if (data) when data is 'N/T', it is crucial to prevent short-circuiting from evaluating it at the end.

Your approach can be illustrated as follows:

return (false || false || true) ? ...
          ^        ^        \____ due to 'N/T' in data
          |        |         
          |        '-------- indication that data is not 0
     because of N/T in data

This leads to a result of true because the || operator only requires one expression to be true.

The solution you should aim for is:

return (data !== 'N/T' && (data === 0 || data)) ? ...
                        ^
                        |
                   remember De-Morgan's Theorem
                (search it up if unfamiliar)

Answer №3

function substituteText(value, replacement) {
    return (value !== 'N/A' || value === 0) ? value : replacement;
}

Answer №4

function updateText(value, fallback) {
        return ((value && value !== 'N/T') || value === 0) ? value : fallback;
};
console.log(updateText('N/T', 'backup'))

Answer №5

/* Give this a shot */

function addDefaultIfEmpty(value, alternative) {
        return (value !== 'N/T' || value === 0) ? value : alternative;
}
addDefaultIfEmpty('N/T', 'alternate')

Answer №6

When using the data in an if statement and passing 'N/T', the value changes to false. However, based on the logic provided, the value should always be true. Consider implementing this alternative solution:

const addText = (data, addAlternative) => (data && (data !== 'N/T' || data === null || data === 0)) ? data : addAlternative;
console.log(addText('N/T', 'alternative'))

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