I need help figuring out how to mention an id using a concatenated variable in the jquery appendTo() method

Question

I need help figuring out how to mention an id using a concatenated variable in the jquery appendTo() method

Using jQuery, I am adding HTML code to a div. One part of this code involves referencing a div's ID by concatenating a variable from a loop.

$(... +
    '<div class="recommendations filter" id="recCards-'+ i +'">' +
    '<div><h5>Recommended Cards</h5></div>' +
        '<ul></ul>' +
    '</div>' +
  ...
 ).appendTo('.someDiv');

Next, I am attempting to append code from another loop into the ul by using the ".recommendations" div's ID in the following manner...

var recCardsList = $(div).attr('id', '.recCards-'"+i+"' ul');

$('<div>'+recCardName+'</div>').appendTo(recCardsList);

I have experimented with various quotation mark combinations, but have been unsuccessful in selecting the div correctly for appending new content.

javascript jquery html css concatenation

Answer 1

Answer №1

It appears that your code is not correctly appending the newly created content to the div due to some errors:

var recCardsList = $(div).attr('id', '.recCards-'"+i+"' ul');
$('<div>'+recCardName+'</div>').appendTo(recCardsList);

The issue lies in using

.attr('id', '.recCards-'"+i+"' ul')

, which does not retrieve the list from the div but rather attempts to update its id.

When passing two arguments to .attr(), the first is the targeted attribute and the second is its new value.

To properly access the div, you should simply use $('#recCards-'+i+' ul') in your loop to target the specific lists. Your revised code should look like this:

var recCardsList = $('#recCards-'+i+' ul');
$('<div>'+recCardName+'</div>').appendTo(recCardsList);

Using $("#someId") retrieves an element with the id="someId" from the page.

Answer 2

It appears that your code is not correctly appending the newly created content to the div due to some errors:

var recCardsList = $(div).attr('id', '.recCards-'"+i+"' ul');
$('<div>'+recCardName+'</div>').appendTo(recCardsList);

The issue lies in using

.attr('id', '.recCards-'"+i+"' ul')

, which does not retrieve the list from the div but rather attempts to update its id.

When passing two arguments to .attr(), the first is the targeted attribute and the second is its new value.

To properly access the div, you should simply use $('#recCards-'+i+' ul') in your loop to target the specific lists. Your revised code should look like this:

var recCardsList = $('#recCards-'+i+' ul');
$('<div>'+recCardName+'</div>').appendTo(recCardsList);

Using $("#someId") retrieves an element with the id="someId" from the page.

Answer 3

Answer №2

Here's a suggestion:

Let's test out this code snippet:

var recommendedCardsList = $(element).attr('id', '.recommendedCards-'+index+' ul');

Answer 4

Here's a suggestion:

Let's test out this code snippet:

var recommendedCardsList = $(element).attr('id', '.recommendedCards-'+index+' ul');

Answer 5

Answer №3

Given the circumstance that the variable i remains within the function's scope, the proposed solution looks like this

'recCards-'+i+' ul'

This approach should work flawlessly, as suggested in the comment. It is recommended to verify the value of variable i using console.log() or alert() because there is a possibility that i could be null based on the provided information.

If both variables are contained within the same function, you might find it helpful to refer to the following post for combining the two loops with appendTo() and append()

jQuery append inside appended element

Answer 6

Given the circumstance that the variable i remains within the function's scope, the proposed solution looks like this

'recCards-'+i+' ul'

This approach should work flawlessly, as suggested in the comment. It is recommended to verify the value of variable i using console.log() or alert() because there is a possibility that i could be null based on the provided information.

If both variables are contained within the same function, you might find it helpful to refer to the following post for combining the two loops with appendTo() and append()

jQuery append inside appended element

Answer 7

Answer №4

Getting the list that way is unlikely. Give this a shot:

let recommendedCardsList = $('#recommendedCards-' + i + ' ul');

Additionally, it's not correct to add a <div> to a <ul>. Instead, use <li>:

$('<li>'+recommendedCardName+'</li>').appendTo(recommendedCardsList);

Answer 8

Getting the list that way is unlikely. Give this a shot:

let recommendedCardsList = $('#recommendedCards-' + i + ' ul');

Additionally, it's not correct to add a <div> to a <ul>. Instead, use <li>:

$('<li>'+recommendedCardName+'</li>').appendTo(recommendedCardsList);

Answer 9

Answer №5

Give this a shot, employ mask and substitute with I,

let strReccards = ".recommCards-INDEX ul";
let recCardsList = $(div).attr('id', recCardIndex.replace("INDEX",I));
$('<div>'+recCardName+'</div>').appendTo(recCardsList);

Answer 10

Give this a shot, employ mask and substitute with I,

let strReccards = ".recommCards-INDEX ul";
let recCardsList = $(div).attr('id', recCardIndex.replace("INDEX",I));
$('<div>'+recCardName+'</div>').appendTo(recCardsList);

I need help figuring out how to mention an id using a concatenated variable in the jquery appendTo() method

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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