I encounter an error if an element is not displayed when using the isDisplayed() method

Question

I encounter an error if an element is not displayed when using the isDisplayed() method

My situation

Going to a specific page
Should I click the element that is displayed
If the element is not displayed, just ignore it

My function

exports.checkButton = function (driver) {

    driver.findElement(By.css(".btn.btn-danger.pull-right.remove-promotion")).then(function(button){ 

        if (button.isDisplayed()) {

            console.log("The element is displayed"); 

    } else { 

            console.log("The element is not displayed");

    }
});

My issue

When the element is not displayed, the message

console.log("The element is not displayed");

is not showing up and I'm getting an error:

Uncaught NoSuchElementError: no such element: Unable to locate the element: {"method":"css selector","selector":".btn.btn-danger.pull-right.remove-promotion"}

javascript selenium selenium-webdriver

Answer 1

Answer №1

isDisplayed() is a method that can only be used when the element is present in the document object model (DOM) but is hidden, for example, if it has a style of display: none. It seems that in your situation, the element does not exist in the DOM when it is not being displayed, which is why you are encountering the NoSuchElementError exception.

Here is a suggested approach:

export.checkButton = function (driver) {    
        driver.findElement(By.css(".btn.btn-danger.pull-right.remove-promotion")).then(function(button){ 
            console.log("Element is displayed");
            button.click();
            return true;
        }).catch(function (ex) {
            console.log("Element is not displayed");
            return false;
        });
}

var display = checkButton(driver);
while (display) {
    display = checkButton(driver);
}

It is recommended to examine the behavior of the DOM in both scenarios - when the element exists and when it does not exist.

Answer 2

isDisplayed() is a method that can only be used when the element is present in the document object model (DOM) but is hidden, for example, if it has a style of display: none. It seems that in your situation, the element does not exist in the DOM when it is not being displayed, which is why you are encountering the NoSuchElementError exception.

Here is a suggested approach:

export.checkButton = function (driver) {    
        driver.findElement(By.css(".btn.btn-danger.pull-right.remove-promotion")).then(function(button){ 
            console.log("Element is displayed");
            button.click();
            return true;
        }).catch(function (ex) {
            console.log("Element is not displayed");
            return false;
        });
}

var display = checkButton(driver);
while (display) {
    display = checkButton(driver);
}

It is recommended to examine the behavior of the DOM in both scenarios - when the element exists and when it does not exist.

Answer 3

Answer №2

Ensuring that an element is visible on the screen requires first confirming its existence within the Document Object Model (DOM). In Java, this can be achieved using the following method:

public boolean isElementPresentInDom(By by) {
    driver.manage().timeouts().implicitlyWait(0, TimeUnit.MILLISECONDS);
    boolean isElementPresent = (driver.findElements(by).size() != 0);
    driver.manage().timeouts().implicitlyWait(driverTimeOut, TimeUnit.MILLISECONDS);
    return isElementPresent;
}

(The equivalent in Javascript may vary slightly, but the concept remains consistent.) If the method returns true, it indicates that the element is present and can be checked for visibility.

Answer 4

Ensuring that an element is visible on the screen requires first confirming its existence within the Document Object Model (DOM). In Java, this can be achieved using the following method:

public boolean isElementPresentInDom(By by) {
    driver.manage().timeouts().implicitlyWait(0, TimeUnit.MILLISECONDS);
    boolean isElementPresent = (driver.findElements(by).size() != 0);
    driver.manage().timeouts().implicitlyWait(driverTimeOut, TimeUnit.MILLISECONDS);
    return isElementPresent;
}

(The equivalent in Javascript may vary slightly, but the concept remains consistent.) If the method returns true, it indicates that the element is present and can be checked for visibility.

Answer 5

Answer №3

When using the .isDisplayed() method, it is important to remember that it assumes the element already exists. If you are encountering an error, it could be due to the element not actually existing on the page. This could be caused by an incorrect locator or possibly the element has not finished loading. To address this, consider using .findElements() (note the plural form) and check that the size is greater than 0 to confirm the element's existence. It is recommended to encapsulate this logic within a function so it can be easily reused when needed. Once you have confirmed the element's existence, then proceed to check its visibility with .isDisplayed(). By following these steps, you can ensure that your code runs smoothly.

Answer 6

When using the .isDisplayed() method, it is important to remember that it assumes the element already exists. If you are encountering an error, it could be due to the element not actually existing on the page. This could be caused by an incorrect locator or possibly the element has not finished loading. To address this, consider using .findElements() (note the plural form) and check that the size is greater than 0 to confirm the element's existence. It is recommended to encapsulate this logic within a function so it can be easily reused when needed. Once you have confirmed the element's existence, then proceed to check its visibility with .isDisplayed(). By following these steps, you can ensure that your code runs smoothly.

I encounter an error if an element is not displayed when using the isDisplayed() method

Answer №1

Answer №2

Answer №3

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