Trying to extract the background color from a CSS string:
"body{
background-color: #dfdfdf;
}
"
The color could also be in rgba(120,120,120) format. I am looking for a way to extract that color using regular expressions. I have tried using this pattern:
^(?=background\-color:\s?)[^;]+$
Unfortunately, it seems like it's not working as expected.
Here is a helpful tip:
/\s*font-size:\s*(\d{2})px/Utilize the exec() function to check the specified string. It receives a regular expression as an argument and produces an array containing the matched value if found, or null if not.
Only the color #dfdfdf is mentioned in the previous answer, but here's a more comprehensive solution:
/\s*background-color:\s*(\#[\w]{6}|rgba\(\d{3},\d{3},\d{3}\))/
Alternatively, you can use:
/\s*background-color:\s*(\#[\w]+|rgba\(\d+,\d+,\d+\))/
I recommend the first option as it specifies the number of characters or digits needed. This will match "#dfdfdf" in "body{background-color: #dfdfdf;}" and "rgba(120,120,120)" in "body{background-color: rgba(123,234,233);}"
EDIT: Upon further consideration, the color could also be rgb or even specified by name, so this revised solution covers all possibilities:
/\s*background-color:\s*([\w(),#]+)/
Make sure to include spaces at the start of the line \s* when matching the entire line (using ^ for the start and $ for the end). Additionally, remember to add a semicolon ; at the end of the line since you specified "one or more non-semicolon characters until the end of the line"
^\s*background\-color:\s?([^;]+);$
UPDATE: The brackets are used to capture the group, for further details check out this resource.
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