Below is the input data:
const arr = [10,20,[40,50,60],70,80,[90,100],111,112];
The desired output is as follows:
{10:10,20:20,'array1':{40:40,50:50,60:60},70:70,80:80,'array2':{90:90,100:100},111:111,112:112}
Below is the input data:
const arr = [10,20,[40,50,60],70,80,[90,100],111,112];
The desired output is as follows:
{10:10,20:20,'array1':{40:40,50:50,60:60},70:70,80:80,'array2':{90:90,100:100},111:111,112:112}
My method involves utilizing the Array.prototype.reduce() function, but it is only capable of handling arrays with a single level of nesting.
const arr = [10,20,[40,50,60],70,80,[90,100],111,112];
let count=1;
let a = arr.reduce((acc,curr) => {
if(Array.isArray(curr)){
let b = curr.reduce((acc1,curr1)=> {
acc1[curr1] = curr1;
return acc1
},{})
acc[`array${count}`] = b;
count+=1;
}
else{
acc[curr] = curr;
}
return acc;
},{})
console.log(a)As the output is an object, the order may not necessarily match the input array structure.
To simplify the process, iterate through the array and create a new object along the way:
let count = 1;
let newObj = {}
arr.forEach((item) => {
if(Number.isInteger(item)){
newObj[item] = item;
} else {
subObj = {}
item.forEach((subItem) => subObj[subItem] = subItem);
newObj[`array${count}`] = subObj;
count += 1;
}
})
Check out this recursive solution using reduce(), which can handle deeply nested arrays as well.
function extractArrayValues(array){
let arrayCounter = 0;
return array.reduce((result, current) => {
if (!Array.isArray(current)) result[current] = current;
else {
arrayCounter += 1;
result[`array${arrayCounter}`] = extractArrayValues(current);
}
return result;
}, {})
}
const sampleArray = [10, 20, [40, 50, 60], 70, 80, [90, 100], 111, 112];
console.log(extractArrayValues(sampleArray));
const nestedArray = [10, 20, [40, 50, 60], 70, 80, [90, 100, [40, 50, 60]], 111, 112];
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