I am implementing a new method in the prototype string, but I am uncertain about its purpose

I am trying to wrap my head around the concept here. It seems like the phrase will pass a part of an array, in this case eve, to the phrase.palindrome method. This method will then process it. First, the var len takes the length of eve and subtracts 1 from it using length -1.. As a result, var len is assigned the number 2, since the length of "eve" is 3. Next, the for loop iterates with var i = 0; i <= len/2; i++.
This translates to var i = 0;;0 <= 1; i++. Is this interpretation correct?
I'm having trouble grasping the logic behind this block:

    for (var i = 0; i <= len/2; i++) {
        if (this.charAt(i) !== this.charAt(len-i)) {
            return false;

Here is the complete code snippet:

String.prototype.palindrome = function() {
    var len = this.length-1;
    for (var i = 0; i <= len/2; i++) {
        if (this.charAt(i) !== this.charAt(len-i)) {
            return false;
        }
    }
    return true;
};

var phrases = ["eve", "kayak", "mom", "wow", "Not a palindrome"];

for (var i = 0; i < phrases.length; i++) {
    var phrase = phrases[i];
    if (phrase.palindrome()) {
        console.log("'"+ phrase + "' is a palindrome");
    } else {
        console.log("'"+ phrase + "' is NOT a palindrome");
    }
 }

Answer №1

This code example demonstrates the concept of checking for palindromes by iterating through a string in both directions. It compares characters at the beginning and end, then moves towards the middle. The condition for a word to be considered a palindrome is that each pair of corresponding characters from opposite ends are the same.

However, it's important to note that there is a major issue with this implementation. Although JavaScript allows for mutating prototypes of built-in types, it's strongly advised against doing so. This practice goes against the principle of least surprise and can lead to unexpected behavior. It's best to treat all types, including built-ins, as immutable and extend functionality through other means.

Answer №2

In my opinion, there seems to be a mistake in this particular line:

for (var i = 0; i <= len/2; i++) {

This could potentially cause issues because the length sometimes can be odd numbers like 3, 5, or 7.

To address this, I have provided alternative examples:

for (var i = 0; i <= Math.floor(len / 2); i++) {
// The same concept applies when using floor with positive numbers, but for negative numbers it functions like ceil.
for (var i = 0; i <= ~~(len / 2); i++) {
// Similarly to using floor, we can consider this as a makeshift polyfill.
for (var i = 0; i <= ~~(len / 2) + (Math.abs(len)>len?-1:0); i++) {

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