Looking to Retrieve the Maximum Value from Nodes
Below is the XML provided:
<xml>
<NewDataSet>
<priorityResult>
<DXCount>32</DXCount>
<LHHight>12</LHHight>
<LHMedium>1</LHMedium>
<RiskPriority>6</RiskPriority>
</priorityResult>
</NewDataSet>
</xml>
The goal is to calculate a value on an XSLT page using this logic:
var priority= parseInt(row["RiskPriority"]);
var newPriority= 0;
if ("DXCount" > 0 )
newPriority= 4;
else if ("LHHight" > 0)
newPriority= 3;
else if ("LHMedium" > 0)
newPriority= 2;
return Math.max(priority, newPriority)
How can I achieve this max value using XSLT?
Here's my attempt at displaying the Node values:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt">
<xsl:output method="html" version="4.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:for-each select="//priorityResult[SessionID != '']">
<p>
Priority :
<xsl:choose>
<xsl:when test="DXCount > 0">
4
</xsl:when>
<xsl:when test="LHHight > 0">
3
</xsl:when>
<xsl:when test="LHMedium > 0">
2
</xsl:when>
<xsl:otherwise>
<xsl:value-of select ="RiskPriority"/>
</xsl:otherwise>
</xsl:choose>
</p>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>