My current object is structured as follows:
const obj = {
happy: 0.6,
neutral: 0.1,
said: 0.3
}
I'm trying to determine the best method to retrieve the property with the highest value (in this case, it would be "happy"). Any suggestions on how I can achieve this?
To retrieve the key-value pairs, you can utilize Object#entries. To find the property with the greatest value, you can make use of Array#reduce:
const obj = { happy: 0.6, neutral: 0.1, said: 0.3 };
const propWithLargestValue = Object.entries(obj).reduce((prop, [key,val]) =>
val > (obj[prop] || Number.MIN_VALUE) ? key : prop
, null);
console.log(propWithLargestValue);If you want to accomplish this task effortlessly, just utilize the power of Object.entries
const obj = {
happy: 0.6,
neutral: 0.1,
sad: 0.3,
};
const result = Object.entries(obj).sort((a, b) => b[1] - a[1])?.[0]?.[0];
console.log(result);If you want to determine the maximum value among the entries of the object and then find the first entry with that value, you can use the following code:
const maxValue = obj => (entries =>
(max => entries.find(([k, v]) => v === max))
(Math.max(...entries.map(([key, val]) => val))))
(Object.entries(obj));
const obj = {
happy: 0.6,
neutral: 0.1,
said: 0.3
};
const [ key, value ] = maxValue(obj);
console.log(key); // happy
console.log(value); // 0.6You can shorten the above function to only 86 bytes:
f=o=>(e=>(m=>e.find(([,x])=>x===m))(Math.max(...e.map(([,v])=>v))))(Object.entries(o))
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