Is there a way to utilize regex in JavaScript for removing all instances of <style>, <style type="text/css">, </style>, and <style type="text/css"/>? I want the outcome to only present the CSS without any style tags.
The code below seems to be ineffective for some reason.
str.replace(/<style\b[^<]*(?:(?!<\/style)<[^<]*)*<\/style>/gi,'');
After reviewing your question, the regex code provided below should be suitable
var regex = /((<style>)|(<style type=.+)|(<<\/style>))/g;
var str = `<style>
styles
</style>
<style type="text/css">
styles
</style>`;
const subst = ``;
// The substituted value will be stored in the result variable
var result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Update
Take a look at the updated regex which removes both the styles and the content within them.
var regex = /((<style>)|(<style type=.+))((\s+)|(\S+)|(\r+)|(\n+))(.+)((\s+)|(\S+)|(\r+)|(\n+))(<<\/style>)/g;
const str = `<style>
styles
</style>
<style type="text/css">
styles
</style>
non html content`;
var subst = ``;
// The substituted value is saved in the result variable
var result = str.replace(regex, subst);
console.log('Substitution result: ', result);
To start off, make sure to correct your regex by using \s+ instead of \b and ensuring the type= argument is set correctly. Also, consider adding the tag variant for better accuracy.
/((<style>)|(<style\s+type=(?:".*"|'.*')\/?)|(<\/style>))/gi
Keep in mind that your string will be read by two engines - first Javascript, then the Regex engine. Make sure to escape characters like \ accordingly.
.replace(/((<style>)|(<style\s+type=(?:".*"|'.*')\\/?)|(<\\/style>))/gi,'');
If you want to extract inline styling, you can utilize the following regular expression:
style="(.*)"
Improvement for eliminating inline style:
.replace(/ design=("[^"]*")|('[^']*')/g, "");
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