Assuming we have the following scenario:
array=[5,5,5,5,3,2];
return Math.max.Apply(Math,array);
How can I modify the code to output the numbers in sequential order from first to last?
Assuming we have the following scenario:
array=[5,5,5,5,3,2];
return Math.max.Apply(Math,array);
How can I modify the code to output the numbers in sequential order from first to last?
Let's address the query presented in the title:
What exactly does the max() function accomplish in JavaScript when an array contains multiple equally large numbers?
The answer is quite straightforward - the max() function does not directly operate on arrays.
To find the maximum value in an array, you can spread the array items as arguments for the max() function:
Math.max(...[1,2,3]) // 3
Alternatively, you can achieve the same result using the apply() method:
Math.max.apply(Math, [1,2,3]) // 3
If the question goes deeper:
What exactly happens when Math.max() encounters multiple instances of the maximum number?
In such cases, the function will simply return that particular number:
const a = [5, 5, 5, 5, 3, 2]
const max = Math.max(...a)
console.log(max) // 5
Another query that may cause confusion:
How can I have the function return the numbers in order from first to last if such a scenario arises?
If you wish to obtain a sorted array, you can use the sort() method on the array:
a.sort() // [2, 3, 5, 5, 5, 5]
For removing duplicates, transforming the array from [5, 5, 5, 5, 3, 2] to [2, 3, 5], you can utilize the Set object with the Array.from() method:
Array.from(new Set(a)) // [2, 3, 5]
If you need further clarification, please provide additional details regarding your question.
To accomplish this task effectively, follow these steps:
let numbers = [5, 5, 5, 5, 3, 2];
let highest = Math.max.apply(null, numbers);
let filteredNumbers = numbers.filter(function(item) {
return item === highest;
});
The filteredNumbers array will now store all the largest elements.
In the illustration by @Clarkie, Math.max is being called more frequently than necessary.
Both Dan and Clarkie mistakenly capitalized "Apply," the correct invocation is Math.max.apply and Math should not be passed in as the first argument.
For a functional example, check out the link below:
Expanding on @Clarkie's brilliant concept. Here's a simplified version...
let numbers = [10, 10, 5, 5, 3, 1],
maxNumber = Math.max(...numbers),
filteredNumbers = numbers.filter(num => num === maxNumber);
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