How can you identify duplicate entries using Mongoose?

I am currently working on a create function and encountering some code that closely resembles this:

if(req.body.test !== undefined)
{
        if(--req.body.test EXISTS IN test (model)--)
        {
            DO STUFF
        }
        else
        {
            DO OTHER STUFF
        }

}

I have been trying to brainstorm a solution for quite some time now, but I am struggling to determine the code needed to handle the 

--req.body.test EXISTS IN test (model)--
part. It seems more complicated than it actually is.

Any guidance or assistance would be greatly appreciated.

Thank you

javascriptnode.jsmongodbexpressmongoose

Answer №1

Is it possible for a count() function to suffice?

if(db.collection.count({test: "test"}) > 2)

Answer №2

Did you experiment with implementing a distinctive index at the MongoDB level and consequently capturing a mongoose uniqueness error?

db.models.createIndex({ sample: 1 }, { unique: true })

Afterwards, perform an insertion and verify the presence of error code 11001. Another approach is to utilize findOne to determine if a document is returned.

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