var array = ['a', 'b', 'c']
function arrayTransform(array) {
if (array.lengths === 0) {
console.log("Empty")
} else {
console.log(array.join());
}
}
arrayTransform(array);The expected result should be 1.a, 2.b, 3.c. Instead, I am receiving abc.
To include the index with each element, consider using the map function to return an array and then utilize join to build the final string.
var array = ['a', 'b', 'c']
function arrayTransform(array) {
if (array.length === 0) {
console.log("Empty")
} else {
return array.map((item, index) => {
return `${index+1}.${item}` // template literals
}).join()
}
}
console.log(arrayTransform(array));To create a unique style by mapping the incremented index with the value and joining them together.
const items = ['apple', 'banana', 'cherry'];
function transformItems(items) {
if (items.length === 0) {
console.log("No items to display");
} else {
console.log(items.map((item, index) => [index + 1, item].join('.')).join());
}
}
transformItems(items);If you're looking to combine elements of an array into a string, the .reduce() method is a great option:
let items = ['x', 'y', 'z'];
let combiner = inputArray => inputArray.length ?
inputArray.reduce((result, currentElement, index) => (result.push(`${index + 1}.${currentElement}`), result), []).join() :
'No elements to combine';
console.log(combiner(items));
console.log(combiner([]));Greetings on Stackoverflow! I recommend utilizing the ES6 method shown here for your query. Feel free to ask if you prefer an ES5 version.
const updatedArray = array.map((value, index) => index + 1 + "." + value);
console.log(updatedArray);
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