How can we organize and display the data from two linked arrays, one containing player names and the other containing

Question

How can we organize and display the data from two linked arrays, one containing player names and the other containing

Looking for help on how to rank 3 players based on their scores using arrays. I've hit a roadblock and need guidance!

Here's a brief example:

Player 1 : Taylor
Score Taylor : 15

Player 2 : Jordan
Score Jordan : 20

Player 3 : Alex
Score Alex : 18

After ranking, we should have:

The first => Jordan with 20 scores
The second => Alex with 18 scores
The third => Taylor with 15 scores

Below is the code snippet I'm currently working on:

function main() {
    var players = new Array();
    var scores = new Array();

    for(i = 0; i<3; i++) {
        players[i] = prompt("Player " + (i+1) + " : ");
        scores[i] = prompt("Score " + (players[i]) + " : ");
    }
}

Appreciate any assistance in advance!

javascript arrays

Answer 1

Answer №1

When faced with the challenge of splitting data into two arrays, one solution could involve using a custom sorting function along with an additional array that stores indices corresponding to the elements in the other arrays:

execute();

function execute() {
  var users = new Array();
  var points = new Array();
  var rankings = new Array();
  for (var i = 0; i < 3; i++) {
    rankings[i] = i;
    users[i] = prompt("User " + (i + 1) + " : ");
    points[i] = prompt("Points for " + (users[i]) + " : ");
  }
  sortIndexedArray(3, rankings, points);
  for (var i = 0; i < 3; i++) {
    var ithUser = users[rankings[i]];
    var ithPoints = points[rankings[i]];
    console.log(ithUser, ithPoints);
  }
}

function sortIndexedArray (n, toBeSorted, toBeCompared) {
  for (var i = 0; i < n - 1; i++) {
    for (var j = i + 1; j < n; j++) {
      var a = toBeCompared[toBeSorted[j]];
      var b = toBeCompared[toBeSorted[i]];
      if (a < b) {
        var min = toBeSorted[j];
        toBeSorted[j] = toBeSorted[i];
        toBeSorted[i] = min;
      }
    }
  }
}

Here is a demonstration of how the code above operates:

users = ["Alice", "Bob", "Charlie"];
points = [5, 7, 4];
rankings = [0, 1, 2];
sortIndexedArray(3, rankings, points);
console.log(rankings);
// [2, 0, 1]
console.log(users[rankings[0]]);
// "Charlie"
console.log(points[rankings[0]]);
// 4

Answer 2

When faced with the challenge of splitting data into two arrays, one solution could involve using a custom sorting function along with an additional array that stores indices corresponding to the elements in the other arrays:

execute();

function execute() {
  var users = new Array();
  var points = new Array();
  var rankings = new Array();
  for (var i = 0; i < 3; i++) {
    rankings[i] = i;
    users[i] = prompt("User " + (i + 1) + " : ");
    points[i] = prompt("Points for " + (users[i]) + " : ");
  }
  sortIndexedArray(3, rankings, points);
  for (var i = 0; i < 3; i++) {
    var ithUser = users[rankings[i]];
    var ithPoints = points[rankings[i]];
    console.log(ithUser, ithPoints);
  }
}

function sortIndexedArray (n, toBeSorted, toBeCompared) {
  for (var i = 0; i < n - 1; i++) {
    for (var j = i + 1; j < n; j++) {
      var a = toBeCompared[toBeSorted[j]];
      var b = toBeCompared[toBeSorted[i]];
      if (a < b) {
        var min = toBeSorted[j];
        toBeSorted[j] = toBeSorted[i];
        toBeSorted[i] = min;
      }
    }
  }
}

Here is a demonstration of how the code above operates:

users = ["Alice", "Bob", "Charlie"];
points = [5, 7, 4];
rankings = [0, 1, 2];
sortIndexedArray(3, rankings, points);
console.log(rankings);
// [2, 0, 1]
console.log(users[rankings[0]]);
// "Charlie"
console.log(points[rankings[0]]);
// 4

Answer 3

Answer №2

Use this code snippet to create a sorted array of players with names and scores

function generateSortedPlayerArray()
            {
                var players = new Array();

                for(i = 0; i<3; i++){
                    let player = {};
                    player.name = prompt("Enter Player " + (i+1) + "'s name: ");
                    player.score = prompt("Enter " + player.name + "'s score: ");
                    players[i] = player;
                }

                players.sort(function(a,b){
                     if (a.score < b.score)
                         return -1;
                     if (a.score> b.score)
                          return 1;
                     return 0;
                })

                console.log(players);

            }

Answer 4

Use this code snippet to create a sorted array of players with names and scores

function generateSortedPlayerArray()
            {
                var players = new Array();

                for(i = 0; i<3; i++){
                    let player = {};
                    player.name = prompt("Enter Player " + (i+1) + "'s name: ");
                    player.score = prompt("Enter " + player.name + "'s score: ");
                    players[i] = player;
                }

                players.sort(function(a,b){
                     if (a.score < b.score)
                         return -1;
                     if (a.score> b.score)
                          return 1;
                     return 0;
                })

                console.log(players);

            }

Answer 5

Answer №3

To efficiently manage and organize users, consider storing each user as an object within an array in the following manner:

function storeUsers(){

    var userList = [];
    for(var i = 0;i<3;i++){
      var user = {};
      user.name = prompt("Enter user name");
      var ranking = prompt("Enter user ranking");
      user.ranking = parseInt(ranking);
      userList.push(user)
    }
    
    console.log("User List");
    userList.forEach(function(user){
      console.log(user.name,user.ranking);
    });
    //Sort the list based on ranking
    userList = userList.sort(function(uA,uB){
      return uA.ranking - uB.ranking;
    });
    userList.forEach(function(user){
      console.log(user.name,user.ranking);
    });
} 

storeUsers();

Answer 6

To efficiently manage and organize users, consider storing each user as an object within an array in the following manner:

function storeUsers(){

    var userList = [];
    for(var i = 0;i<3;i++){
      var user = {};
      user.name = prompt("Enter user name");
      var ranking = prompt("Enter user ranking");
      user.ranking = parseInt(ranking);
      userList.push(user)
    }
    
    console.log("User List");
    userList.forEach(function(user){
      console.log(user.name,user.ranking);
    });
    //Sort the list based on ranking
    userList = userList.sort(function(uA,uB){
      return uA.ranking - uB.ranking;
    });
    userList.forEach(function(user){
      console.log(user.name,user.ranking);
    });
} 

storeUsers();

Answer 7

Answer №4

Here is a simple implementation using the push method to add objects to an array and the sort method to sort the array based on the score. Take a look at the code snippet below.

var array=[];

function add(){
    var player={};
    player.name=prompt("Player " + (array.length+1) + " : ");
    player.score=parseInt(prompt("Score " + (player.name) + " : "));
    array.push(player);
    array.sort((a,b)=>a.score<b.score)
    console.log(array);
}

<button onclick="add()">Add Player</button>

Answer 8

Here is a simple implementation using the push method to add objects to an array and the sort method to sort the array based on the score. Take a look at the code snippet below.

var array=[];

function add(){
    var player={};
    player.name=prompt("Player " + (array.length+1) + " : ");
    player.score=parseInt(prompt("Score " + (player.name) + " : "));
    array.push(player);
    array.sort((a,b)=>a.score<b.score)
    console.log(array);
}

<button onclick="add()">Add Player</button>

Answer 9

Answer №5

Instead of using separate arrays, it is recommended to use an array of objects like this:

let data = [
  {name: 'Jeremy', score: 12},
  {name: 'Julien', score: 18},
  {name: 'Olivia', score: 22}
];

You can then easily sort and display the results using .sort():

let data = [
  {name: 'Jeremy', score: 12},
  {name: 'Julien', score: 18},
  {name: 'Olivia', score: 22}
];

data.sort((a, b) => b.score - a.score);

console.log(`The first player is ${data[0].name} with ${data[0].score} points`);
console.log(`The second player is ${data[1].name} with ${data[1].score} points`);
console.log(`The third player is ${data[2].name} with ${data[2].score} points`);

If you prefer to stick with 2 separate arrays, you can still combine them into an array of objects and display the sorted results.

let players = ['Jeremy', 'Julien', 'Olivia'];
let scores = [12, 18, 22];

function printResult(playersArr, scoresArr) {
  let combinedArray = playersArr.reduce((arr, name, index) => (arr.push({name, score: scoresArr[index]}), arr), [])
           .sort((a, b) => b.score - a.score);
                 
  console.log(`The top player is ${combinedArray[0].name} with ${combinedArray[0].score} points`);
  console.log(`The second player is ${combinedArray[1].name} with ${combinedArray[1].score} points`);
  console.log(`The third player is ${combinedArray[2].name} with ${combinedArray[2].score} points`);
}

printResult(players, scores);

Helpful Resources:

Answer 10

Instead of using separate arrays, it is recommended to use an array of objects like this:

let data = [
  {name: 'Jeremy', score: 12},
  {name: 'Julien', score: 18},
  {name: 'Olivia', score: 22}
];

You can then easily sort and display the results using .sort():

let data = [
  {name: 'Jeremy', score: 12},
  {name: 'Julien', score: 18},
  {name: 'Olivia', score: 22}
];

data.sort((a, b) => b.score - a.score);

console.log(`The first player is ${data[0].name} with ${data[0].score} points`);
console.log(`The second player is ${data[1].name} with ${data[1].score} points`);
console.log(`The third player is ${data[2].name} with ${data[2].score} points`);

If you prefer to stick with 2 separate arrays, you can still combine them into an array of objects and display the sorted results.

let players = ['Jeremy', 'Julien', 'Olivia'];
let scores = [12, 18, 22];

function printResult(playersArr, scoresArr) {
  let combinedArray = playersArr.reduce((arr, name, index) => (arr.push({name, score: scoresArr[index]}), arr), [])
           .sort((a, b) => b.score - a.score);
                 
  console.log(`The top player is ${combinedArray[0].name} with ${combinedArray[0].score} points`);
  console.log(`The second player is ${combinedArray[1].name} with ${combinedArray[1].score} points`);
  console.log(`The third player is ${combinedArray[2].name} with ${combinedArray[2].score} points`);
}

printResult(players, scores);

Helpful Resources:

How can we organize and display the data from two linked arrays, one containing player names and the other containing

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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