To effectively implement this in Angular, one approach might be to utilize ngInclude for conditionally loading an ngTemplate. The code snippet below demonstrates how this can be achieved:
<script type="text/ng-template" id="development">
<script src="js/services.js"></script>
<script src="js/controllers.js"></script>
script src="js/directives.js"></script>
</script>
<script type="text/ng-template" id="production">
<script src="js/all.min.js"></script>
</script>
<div id="javascripts" ng-include="dev ? 'development' : 'production'"></div>
If your controller involves the use of $scope, simply set $scope.dev to true for including development JavaScript, or false to opt for the production file.
It may also be advisable to explore task runners for a more efficient method. Additionally, consider leveraging environment variables to dictate the project's current state.
Incorporating Gulp for this purpose, you can make use of the gulp-html-replace package. A sample task utilizing this package is outlined below:
var gulp = require('gulp');
var htmlreplace = require('gulp-html-replace');
gulp.task('replace-js', function(){
if (process.env.NODE_ENV === 'production') {
gulp.src('index.html')
.pipe(htmlreplace({
'js': ['js/services.js', 'js/controllers.js', 'js/directives.js']
}))
}
});
Given this HTML structure:
<!-- build:js -->
<script src="js/all.min.js"></script>
<!-- endbuild -->
(Please note that the following instructions involve node-specific operations and may need adjustment according to your system)
Upon running Gulp, it is imperative to set the environment variable, as seen in the if statement above with process.env.NODE_ENV. This can be done by executing Gulp as follows:
set NODE_ENV=production && gulp replace-js
Depending on your operating system, you may need to refer to specific guidelines like "set environment variable node YOUR_OS" in case any issues arise.
For easier access, add the command to your package.json under the scripts key, incorporating a setup similar to the example provided below:
"scripts": {
"replace-js": "set NODE_ENV=production && gulp replace-js"
}
This way, you can execute the designated command effortlessly instead of manually typing out the entire expression:
npm run replace-js
Please bear in mind that these details are based on memory and assuming no errors have been made, ensuring clarity for seamless execution.