Looking for a way to treat accented characters as equivalent to their non-accented counterparts in my code. Here's what I have so far:
var re = new RegExp(string, 'i');
if(target.search(re) == 0) { }
Currently, the code ignores the character's case. How can I also make it ignore whether the character is accented or not?
It seems like the best approach would be to eliminate the diacritics before applying your regular expression.
You might want to consider using this specific function that I stumbled upon here :
function removeAccentMarks(str)
{
var patterns=[
{pattern:/[\xC0-\xC6]/g, replacement:'A'},
{pattern:/[\xE0-\xE6]/g, replacement:'a'},
{pattern:/[\xC8-\xCB]/g, replacement:'E'},
{pattern:/[\xE8-\xEB]/g, replacement:'e'},
{pattern:/[\xCC-\xCF]/g, replacement:'I'},
{pattern:/[\xEC-\xEF]/g, replacement:'i'},
{pattern:/[\xD2-\xD6]/g, replacement:'O'},
{pattern:/[\xF2-\xF6]/g, replacement:'o'},
{pattern:/[\xD9-\xDC]/g, replacement:'U'},
{pattern:/[\xF9-\xFC]/g, replacement:'u'},
{pattern:/[\xD1]/g, replacement:'N'},
{pattern:/[\xF1]/g, replacement:'n'} ];
for(var j=0, length=patterns.length; j<length; j++)
str=str.replace(patterns[j].pattern, patterns[j].replacement);
return str;
}
utilizes the semplice library
var latin_map = {
'Á': 'A', // LATIN CAPITAL LETTER A WITH ACUTE
'Ă': 'A', // LATIN CAPITAL LETTER A WITH BREVE
...
'ᵥ': 'v', // LATIN SUBSCRIPT SMALL LETTER V
'ₓ': 'x', // LATIN SUBSCRIPT SMALL LETTER X
};
String.prototype.latinise = function() {
return this.replace(/[^A-Za-z0-9]/g, function(x) { return latin_map[x] || x; })
};
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