How can I extract the domain name using a regular expression in JavaScript?

I am struggling with creating a regular expression to extract the main domain name from a URL. The URLs I have are:

http://domain.com/return/java.php?hello.asp
http://www.domain.com/return/java.php?hello.asp
http://blog.domain.net/return/java.php?hello.asp
http://us.blog.domain.co.us/return/java.php?hello.asp
http://domain.co.uk
http://domain.net
http://www.blog.domain.co.ca/return/java.php?hello.asp
http://us.domain.com/return/

From these examples, I want to only retrieve domain as the output of my regular expression. How can this be achieved? My current attempt is:

var url = urls.match(/[^.]*.(com|net|org|info|coop|int|co\.uk|org\.uk|ac\.uk|uk)/g);

However, this does not work for:

  http://domain.net

If you have any suggestions or solutions, please help me out.

Answer №1

You have the option to utilize URL instead of regular expressions

var url  = new URL("http://website.com/return/java.php?hello.asp");
console.log(url.hostname);
=> website.com

OR

If you prefer including the protocol too

var url  = new URL("http://website.com/return/java.php?hello.asp");
console.log(url.protocol+"//"+url.hostname);
= > http://website.com

Answer №2

Do you think this could be helpful?

(http|https|ftp):\/\/([a-zA-Z0-9.])+/g

This regex pattern matches the following URLs:

http://domain.com
http://www.domain.com
http://blog.domain.net
http://us.blog.domain.co.us
http://domain.co.uk
http://domain.net
http://www.blog.domain.co.ca
http://us.domain.com

Answer №3

Here's a revised solution with some adjustments to the regex pattern:

url.match(/https?:\/\/[^/]+((?=\/)|$)/g);
// Tested using Chrome 38+ on Windows 7

This regex pattern is essentially looking for either a slash / or the end of the string $.

Updated the jsFiddle link to include inline Stackoverflow-Code:

var urls = ['http://domain.com/return/java.php?hello.asp',
  'http://www.domain.com/return/java.php?hello.asp',
  'http://blog.domain.net/return/java.php?hello.asp',
  'http://us.blog.domain.co.us/return/java.php?hello.asp',
  'http://domain.co.uk',
  'http://domain.net',
  'http://www.blog.domain.co.ca/return/java.php?hello.asp',
  'http://us.domain.com/return/'
];

var htmlConsole = document.getElementById("result");
var htmlTab = "    ";
var htmlNewLine = "<br />";

htmlConsole.innerHTML = "";
for (var id in urls) {

  htmlConsole.innerHTML += "URL: " + urls[id] + htmlNewLine;

  var matchResults = urls[id].match(/https?:\/\/[^/]+((?=\/)|$)/g);

  for (var innerIdx in matchResults) {
    htmlConsole.innerHTML += htmlTab + "Match Number: " + innerIdx + " Match Value: " + matchResults[innerIdx] + htmlNewLine;
  }

  htmlConsole.innerHTML += htmlNewLine;

}
<div id="result">
</div>

Answer №4

var url = urls.match(/[^./]*.(com|net|org|info|coop|int|co\.uk|co\.us|co\.ca|org\.uk|ac\.uk|uk)/g);

Recently updated code by adding a forward slash and modifying the list of top-level domains to align with specific examples.
I suggest avoiding including a long list of top-level domains within a regular expression since it could become unwieldy. Check out this link for more information: http://en.wikipedia.org/wiki/List_of_Internet_top-level_domains

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