How can I ensure all data has been loaded via AJAX before rendering the page in Angular?

On my webpage, I need to load a matrix of data in the form of a table. To achieve this, I make three requests to obtain all the necessary data:

  • Data for columns
  • Data for rows
  • Data for relationships

Once I have gathered all the data, I utilize a function called

getRelation(columnIndex, rowIndex)
to retrieve the relationship data.

However, if the rows are loaded before the columns, Angular will attempt to execute the getRelation method for rendering. This can lead to an error because the column data is not yet available.

I could potentially include an if condition within my function to handle this scenario, but I am curious if there is a better way to address this issue?

this.relations = [];
this.columns = [];
this.rows = [];
this.getRalation = function getRalation(columnIndex, rowIndex) {
    var column= this.columns[columnIndex];
    var row= this.rows[rowIndex]

    var relation = $myService.getSomthing(this.relations, column.ID, row.ID);

    return relation;
}.bind(this);

$http.post(url, {}).then(function(res) {
    this.rows = res.data;
}.bind(this));

// similar code implementation for columns and relations

Answer №1

implementing $q in AngularJS:

$q.all([/*fetch data from row*/,/*retrieve data from column*/]).then(function(result){
     var rows = result[0];
     var columns = result[1];
     //analyze rows and cols, apply getRalation function here

});

Answer №2

To optimize your code, consider performing row calculations after columns. Utilizing promises in JavaScript can help with this process. A recommended library for handling promises is Q.

https://github.com/kriskowal/q

Answer №3

According to @Vanojx1, it is recommended to utilize the $q service which helps in combining promises. To gain a better understanding, refer to the $q documentation.

var rows = $http.post(url, {}).then(function(res) {
    return res.data;
})


var columns = $http.post(url, {}).then(function(res) {
    return res.data;
})

var relationship = $http.post(url, {}).then(function(res) {
    return res.data;
})


var results = [];

$q.all([rows, columns, relationship]).then(function(result){
    for (var i = 0; i < result.length; i++){
        results.push(result[i]);
    }
    result[0] //rows data
    result[1] //columns data
    result[2] //relationship data

});

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