If my sessionStorage has three objects with keys named foo, foobar, and baz, is there a method to remove or delete all items in sessionStorage that have the key foo? After this operation, only the item with the key baz would remain.
If my sessionStorage has three objects with keys named foo, foobar, and baz, is there a method to remove or delete all items in sessionStorage that have the key foo? After this operation, only the item with the key baz would remain.
Updated on September 20, 2014: Jordan Trudgett pointed out that the reverse loop is more suitable for this scenario.
To achieve this programmatically, you can utilize sessionStorage which provides a limited set of methods such as getItem(key), setItem(key, value), removeItem(key), key(position), clear(), and length():
var n = sessionStorage.length;
while(n--) {
var key = sessionStorage.key(n);
if(/foo/.test(key)) {
sessionStorage.removeItem(key);
}
}
For more detailed information, refer to Nicholas C. Zakas' blog post:
A possible approach could be
Get all keys in the sessionStorage
.filter(function(key) { return /bar/.test(key); })
.forEach(function(key) {
Remove item from sessionStorage;
});
To access and manipulate properties in both local and sessionStorage objects, you can use the following code:
for (var item in localStorage) {
if (localStorage.hasOwnProperty(item) && item == "myKey") {
localStorage.removeItem(item);
}
}This code allows you to remove values based on a specific key, such as "myKey" in this example.
Delete all session storage data:
sessionStorage.clear()
Give this a shot:
for (let key of Object.keys(localStorage)) {
localStorage.removeItem(key);
}
By using this code, you can clear all items stored in the local storage
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