This particular button actually opens a popup, even though it is located on the same page.
![click here for image description][1]
I attempted to interact with the element using the following code:
driver.findElement(By.tagName("td")).findElement(By.id("leadCaptureList_leadCaptureList_assignCampaign")).click();
However, I encountered an error message stating "Unable to locate element: {"method":"id","selector":"leadCaptureList_leadCaptureList_assignCampaign"}"
In case the other button is not located within a td element, you can utilize the code provided below.
driver.findElement(By.xpath("//td/input[@id='leadCaptureList_leadCaptureList_assignCampaign']")).click();
Alternatively, if both buttons share the same xpath, you can incorporate an index in the xpath as shown:
driver.findElement(By.xpath("(//td/input[@id='leadCaptureList_leadCaptureList_assignCampaign'])[1]")).click(); //Make sure to replace [1] with the correct index
If the above methods do not yield results (which seem unlikely), it might be necessary to inspect the HTML of the second button to identify any disparities between the two buttons.
Following Husam's advice, remember to include the parent in your selector, like the div that appears.
//let's say the popup div has an id of "popup"$("#popup #button").click() could be what you're looking for.
I hope this information proves useful.
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