How can AngularJS handle uploading multipart form data along with a file?

Question

How can AngularJS handle uploading multipart form data along with a file?

Although I am new to angular.js, I have a solid understanding of the fundamentals.

My goal is to upload both a file and some form data as multipart form data. I've learned that this is not a built-in feature of angular, but third-party libraries can help achieve this. I tried using angular-file-upload by cloning it from git, but I still can't figure out how to submit a basic form along with a file.

Could someone kindly share an example along with the HTML and JavaScript code on how to accomplish this task?

javascript forms angularjs post multipartform-data

Answer 1

Answer №1

To begin with

No special changes are required in the structure, specifically in the html input tags.

<input accept="image/*" name="file" ng-value="fileToUpload"
       value="{{fileToUpload}}" file-model="fileToUpload"
       set-file-data="fileToUpload = value;" 
       type="file" id="my_file" />

1.2 develop your own directive,

.directive("fileModel",function() {
return {
restrict: 'EA',
scope: {
setFileData: "&"
},
link: function(scope, ele, attrs) {
ele.on('change', function() {
scope.$apply(function() {
var val = ele[0].files[0];
scope.setFileData({ value: val });
});
});
}
}
})

In the module with $httpProvider, add dependencies like (Accept, Content-Type etc) with multipart/form-data. (It is suggested to receive response in json format) For example:

$httpProvider.defaults.headers.post['Accept'] = 'application/json, text/javascript'; $httpProvider.defaults.headers.post['Content-Type'] = 'multipart/form-data; charset=utf-8';

Next, create a separate function in the controller to handle form submissions. such as the code below:
In the service function, handle the "responseType" parameter intentionally so that the server does not throw a "byteerror".
Use transformRequest to modify the request format with attached identity.
Keep withCredentials : false for HTTP authentication information.

in controller:

  // write this accordingly so that your file object 
  // will be passed in the service call below.
  fileUpload.uploadFileToUrl(file); 


in service:

  .service('fileUpload', ['$http', 'ajaxService',
    function($http, ajaxService) {

      this.uploadFileToUrl = function(data) {
        var data = {}; //file object 

        var fd = new FormData();
        fd.append('file', data.file);

        $http.post("endpoint server path where the file is being sent", fd, {
            withCredentials: false,
            headers: {
              'Content-Type': undefined
            },
            transformRequest: angular.identity,
            params: {
              fd
            },
            responseType: "arraybuffer"
          })
          .then(function(response) {
            var data = response.data;
            var status = response.status;
            console.log(data);

            if (status == 200 || status == 202) //do necessary actions on success
            else // handle errors if needed 
          })
          .catch(function(error) {
            console.log(error.status);

            // handle other scenarios
          });
      }
    }
  }])

<script src="//unpkg.com/angular/angular.js"></script>

Answer 2

To begin with

No special changes are required in the structure, specifically in the html input tags.

<input accept="image/*" name="file" ng-value="fileToUpload"
       value="{{fileToUpload}}" file-model="fileToUpload"
       set-file-data="fileToUpload = value;" 
       type="file" id="my_file" />

1.2 develop your own directive,

.directive("fileModel",function() {
return {
restrict: 'EA',
scope: {
setFileData: "&"
},
link: function(scope, ele, attrs) {
ele.on('change', function() {
scope.$apply(function() {
var val = ele[0].files[0];
scope.setFileData({ value: val });
});
});
}
}
})

In the module with $httpProvider, add dependencies like (Accept, Content-Type etc) with multipart/form-data. (It is suggested to receive response in json format) For example:

$httpProvider.defaults.headers.post['Accept'] = 'application/json, text/javascript'; $httpProvider.defaults.headers.post['Content-Type'] = 'multipart/form-data; charset=utf-8';

Next, create a separate function in the controller to handle form submissions. such as the code below:
In the service function, handle the "responseType" parameter intentionally so that the server does not throw a "byteerror".
Use transformRequest to modify the request format with attached identity.
Keep withCredentials : false for HTTP authentication information.

in controller:

  // write this accordingly so that your file object 
  // will be passed in the service call below.
  fileUpload.uploadFileToUrl(file); 


in service:

  .service('fileUpload', ['$http', 'ajaxService',
    function($http, ajaxService) {

      this.uploadFileToUrl = function(data) {
        var data = {}; //file object 

        var fd = new FormData();
        fd.append('file', data.file);

        $http.post("endpoint server path where the file is being sent", fd, {
            withCredentials: false,
            headers: {
              'Content-Type': undefined
            },
            transformRequest: angular.identity,
            params: {
              fd
            },
            responseType: "arraybuffer"
          })
          .then(function(response) {
            var data = response.data;
            var status = response.status;
            console.log(data);

            if (status == 200 || status == 202) //do necessary actions on success
            else // handle errors if needed 
          })
          .catch(function(error) {
            console.log(error.status);

            // handle other scenarios
          });
      }
    }
  }])

<script src="//unpkg.com/angular/angular.js"></script>

Answer 3

Answer №2

This is essentially a recreation of the demo page for a specific project, showcasing the process of uploading a single file upon form submission with real-time upload progress display.

(function (angular) {
'use strict';

angular.module('uploadModule', [])
    .controller('uploadCtrl', [
        '$scope',
        '$upload',
        function ($scope, $upload) {
            $scope.model = {};
            $scope.selectedFile = [];
            $scope.uploadProgress = 0;

            $scope.uploadFile = function () {
                var file = $scope.selectedFile[0];
                $scope.upload = $upload.upload({
                    url: 'api/upload',
                    method: 'POST',
                    data: angular.toJson($scope.model),
                    file: file
                }).progress(function (evt) {
                    $scope.uploadProgress = parseInt(100 * evt.loaded / evt.total, 10);
                }).success(function (data) {
                    //do something
                });
            };

            $scope.onFileSelect = function ($files) {
                $scope.uploadProgress = 0;
                $scope.selectedFile = $files;
            };
        }
    ])
    .directive('progressBar', [
        function () {
            return {
                link: function ($scope, el, attrs) {
                    $scope.$watch(attrs.progressBar, function (newValue) {
                        el.css('width', newValue.toString() + '%');
                    });
                }
            };
        }
    ]);
 }(angular));

HTML

<form ng-submit="uploadFile()">
   <div class="row">
         <div class="col-md-12">
                  <input type="text" ng-model="model.fileDescription" />
                  <input type="number" ng-model="model.rating" />
                  <input type="checkbox" ng-model="model.isAGoodFile" />
                  <input type="file" ng-file-select="onFileSelect($files)">
                  <div class="progress" style="margin-top: 20px;">
                    <div class="progress-bar" progress-bar="uploadProgress" role="progressbar">
                      <span ng-bind="uploadProgress"></span>
                      <span>%</span>
                    </div>
                  </div>

                  <button button type="submit" class="btn btn-default btn-lg">
                    <i class="fa fa-cloud-upload"></i>
                    &nbsp;
                    <span>Upload File</span>
                  </button>
                </div>
              </div>
            </form>

UPDATE: Included sending model data to the server alongside the file in the post request.

The information from the input fields will be included in the data property of the post and can be accessed as standard form values on the server side.

Answer 4

This is essentially a recreation of the demo page for a specific project, showcasing the process of uploading a single file upon form submission with real-time upload progress display.

(function (angular) {
'use strict';

angular.module('uploadModule', [])
    .controller('uploadCtrl', [
        '$scope',
        '$upload',
        function ($scope, $upload) {
            $scope.model = {};
            $scope.selectedFile = [];
            $scope.uploadProgress = 0;

            $scope.uploadFile = function () {
                var file = $scope.selectedFile[0];
                $scope.upload = $upload.upload({
                    url: 'api/upload',
                    method: 'POST',
                    data: angular.toJson($scope.model),
                    file: file
                }).progress(function (evt) {
                    $scope.uploadProgress = parseInt(100 * evt.loaded / evt.total, 10);
                }).success(function (data) {
                    //do something
                });
            };

            $scope.onFileSelect = function ($files) {
                $scope.uploadProgress = 0;
                $scope.selectedFile = $files;
            };
        }
    ])
    .directive('progressBar', [
        function () {
            return {
                link: function ($scope, el, attrs) {
                    $scope.$watch(attrs.progressBar, function (newValue) {
                        el.css('width', newValue.toString() + '%');
                    });
                }
            };
        }
    ]);
 }(angular));

HTML

<form ng-submit="uploadFile()">
   <div class="row">
         <div class="col-md-12">
                  <input type="text" ng-model="model.fileDescription" />
                  <input type="number" ng-model="model.rating" />
                  <input type="checkbox" ng-model="model.isAGoodFile" />
                  <input type="file" ng-file-select="onFileSelect($files)">
                  <div class="progress" style="margin-top: 20px;">
                    <div class="progress-bar" progress-bar="uploadProgress" role="progressbar">
                      <span ng-bind="uploadProgress"></span>
                      <span>%</span>
                    </div>
                  </div>

                  <button button type="submit" class="btn btn-default btn-lg">
                    <i class="fa fa-cloud-upload"></i>
                    &nbsp;
                    <span>Upload File</span>
                  </button>
                </div>
              </div>
            </form>

UPDATE: Included sending model data to the server alongside the file in the post request.

The information from the input fields will be included in the data property of the post and can be accessed as standard form values on the server side.

Answer 5

Answer №3

Sending Files Directly for Better Efficiency

Utilizing base64 encoding with base64 encoding and

Content-Type: multipart/form-data

can result in an additional 33% overhead. To improve efficiency, it is recommended to send the files directly:

Implementing Multiple `$http.post` Requests from a FileList

$scope.upload = function(url, fileList) {
    var config = {
      headers: { 'Content-Type': undefined },
      transformResponse: angular.identity
    };
    var promises = fileList.map(function(file) {
      return $http.post(url, file, config);
    });
    return $q.all(promises);
};

While sending a POST request using a File object, ensure that 'Content-Type': undefined is set. This allows the XHR send method to recognize the File object automatically setting the content type.

Demonstrating the Functionality of "select-ng-files" Directive Working with `ng-model`¹

The default behavior of the <input type=file> element does not align with the ng-model directive. A custom directive is required for this purpose:

angular.module("app",[]);

angular.module("app").directive("selectNgFiles", function() {
  return {
    require: "ngModel",
    link: function postLink(scope,elem,attrs,ngModel) {
      elem.on("change", function(e) {
        var files = elem[0].files;
        ngModel.$setViewValue(files);
      })
    }
  }
});

<script src="//unpkg.com/angular/angular.js"></script>
  <body ng-app="app">
    <h1>AngularJS Input `type=file` Demo</h1>
    
    <input type="file" select-ng-files ng-model="fileList" multiple>
    
    <h2>Files</h2>
    <div ng-repeat="file in fileList">
      {{file.name}}
    </div>
  </body>

Answer 6

Sending Files Directly for Better Efficiency

Utilizing base64 encoding with base64 encoding and

Content-Type: multipart/form-data

can result in an additional 33% overhead. To improve efficiency, it is recommended to send the files directly:

Implementing Multiple `$http.post` Requests from a FileList

$scope.upload = function(url, fileList) {
    var config = {
      headers: { 'Content-Type': undefined },
      transformResponse: angular.identity
    };
    var promises = fileList.map(function(file) {
      return $http.post(url, file, config);
    });
    return $q.all(promises);
};

While sending a POST request using a File object, ensure that 'Content-Type': undefined is set. This allows the XHR send method to recognize the File object automatically setting the content type.

Demonstrating the Functionality of "select-ng-files" Directive Working with `ng-model`¹

The default behavior of the <input type=file> element does not align with the ng-model directive. A custom directive is required for this purpose:

angular.module("app",[]);

angular.module("app").directive("selectNgFiles", function() {
  return {
    require: "ngModel",
    link: function postLink(scope,elem,attrs,ngModel) {
      elem.on("change", function(e) {
        var files = elem[0].files;
        ngModel.$setViewValue(files);
      })
    }
  }
});

<script src="//unpkg.com/angular/angular.js"></script>
  <body ng-app="app">
    <h1>AngularJS Input `type=file` Demo</h1>
    
    <input type="file" select-ng-files ng-model="fileList" multiple>
    
    <h2>Files</h2>
    <div ng-repeat="file in fileList">
      {{file.name}}
    </div>
  </body>

Answer 7

Answer №4

If you're looking to send image and form data together, give this method a try

<div class="form-group ml-5 mt-4" ng-app="myApp" ng-controller="myCtrl">
                    <label for="image_name">Image Name:</label>
                    <input type="text"   placeholder="Image name" ng-model="fileName" class="form-control" required>
                    <br>

                    <br>
                    <input id="file_src" type="file"   accept="image/jpeg" file-input="files"   >
                    <br>
                        {{file_name}}
            <img class="rounded mt-2 mb-2 " id="prvw_img" width="150" height="100" >
                    <hr>
                      <button class="btn btn-info" ng-click="uploadFile()">Upload</button>
                        <br>

                       <div ng-show = "IsVisible" class="alert alert-info w-100 shadow mt-2" role="alert">
              <strong> {{response_msg}} </strong>
            </div>
                            <div class="alert alert-danger " id="filealert"> <strong> File Size should be less than 4 MB </strong></div>
                    </div>

Angular JS Code

    var app = angular.module("myApp", []);
 app.directive("fileInput", function($parse){
      return{
           link: function($scope, element, attrs){
                element.on("change", function(event){
                     var files = event.target.files;


                     $parse(attrs.fileInput).assign($scope, element[0].files);
                     $scope.$apply();
                });
           }
      }
 });
 app.controller("myCtrl", function($scope, $http){
      $scope.IsVisible = false;
      $scope.uploadFile = function(){
           var form_data = new FormData();
           angular.forEach($scope.files, function(file){
                form_data.append('file', file); //form file
                                form_data.append('file_Name',$scope.fileName); //form text data
           });
           $http.post('upload.php', form_data,
           {
                //'file_Name':$scope.file_name;
                transformRequest: angular.identity,
                headers: {'Content-Type': undefined,'Process-Data': false}
           }).success(function(response){
             $scope.IsVisible = $scope.IsVisible = true;
                      $scope.response_msg=response;
               // alert(response);
               // $scope.select();
           });
      }

 });

Answer 8

If you're looking to send image and form data together, give this method a try

<div class="form-group ml-5 mt-4" ng-app="myApp" ng-controller="myCtrl">
                    <label for="image_name">Image Name:</label>
                    <input type="text"   placeholder="Image name" ng-model="fileName" class="form-control" required>
                    <br>

                    <br>
                    <input id="file_src" type="file"   accept="image/jpeg" file-input="files"   >
                    <br>
                        {{file_name}}
            <img class="rounded mt-2 mb-2 " id="prvw_img" width="150" height="100" >
                    <hr>
                      <button class="btn btn-info" ng-click="uploadFile()">Upload</button>
                        <br>

                       <div ng-show = "IsVisible" class="alert alert-info w-100 shadow mt-2" role="alert">
              <strong> {{response_msg}} </strong>
            </div>
                            <div class="alert alert-danger " id="filealert"> <strong> File Size should be less than 4 MB </strong></div>
                    </div>

Angular JS Code

    var app = angular.module("myApp", []);
 app.directive("fileInput", function($parse){
      return{
           link: function($scope, element, attrs){
                element.on("change", function(event){
                     var files = event.target.files;


                     $parse(attrs.fileInput).assign($scope, element[0].files);
                     $scope.$apply();
                });
           }
      }
 });
 app.controller("myCtrl", function($scope, $http){
      $scope.IsVisible = false;
      $scope.uploadFile = function(){
           var form_data = new FormData();
           angular.forEach($scope.files, function(file){
                form_data.append('file', file); //form file
                                form_data.append('file_Name',$scope.fileName); //form text data
           });
           $http.post('upload.php', form_data,
           {
                //'file_Name':$scope.file_name;
                transformRequest: angular.identity,
                headers: {'Content-Type': undefined,'Process-Data': false}
           }).success(function(response){
             $scope.IsVisible = $scope.IsVisible = true;
                      $scope.response_msg=response;
               // alert(response);
               // $scope.select();
           });
      }

 });

How can AngularJS handle uploading multipart form data along with a file?

Answer №1

Answer №2

Answer №3

Sending Files Directly for Better Efficiency

Implementing Multiple `$http.post` Requests from a FileList

Demonstrating the Functionality of "select-ng-files" Directive Working with `ng-model`¹

Answer №4

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How can AngularJS handle uploading multipart form data along with a file?

Answer №1

Answer №2

Answer №3

Sending Files Directly for Better Efficiency

Implementing Multiple $http.post Requests from a FileList

Demonstrating the Functionality of "select-ng-files" Directive Working with ng-model1

Answer №4

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What could be the reason why my useRouter function isn't working as expected?

Zooming on a webpage is causing problems

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I am experiencing difficulties with the ng-disabled directive in AngularJS as it is not functioning

Unable to post form data into database due to Javascript undefined data situation

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