How about using curly braces to break apart a string?

'{5}<blah>{0}</blah>'

i wish to transform it into:

['{5}', '<blah>', '{0}', '</blah>']

i am currently using: ________.split(/({.*?})/);

but it does not work when curly bracket is the first character like in this example:

'{0}<blah>'

this results in: ['', '{0}', '<blah>'] ... making a 3 element array instead of 2

what could be the issue with my regex pattern?

Many thanks!

Answer №1

Your regular expression is correct, however the problem lies in the utilization of the split function. Split function divides a string based on a given delimiter, resulting in an array with elements before and after the split item.

To resolve this issue, you can simply verify if the first element is equal to '' and eliminate it if true.

Answer №2

Here is the solution:

split(/((?!^)\{.*?\})/)

The unique feature of this regex pattern is the negative lookahead -- (?!^) -- which only matches if the string does not start at the beginning.

Answer №3

How do you feel about this code snippet:

'{5}<blah>{0}</blah>'.split(/{([^}]+)}/g)

The values inside the curly braces are extracted every two items starting from the second item.

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