Here's a unique way to combine two arrays based on the name value in JavaScript using the includes method

Is there a way to efficiently merge two arrays by name, even if one array has "Ana Marie Cruz" while the other has "Anna Marie"? I've tried doing it in ES6 but can't seem to figure it out. Any suggestions on the best approach?

let arr1 = [{
  name: "Shaina",
  age: "27"
}, {
  name: "Ana Marie Cruz",
  "age": "35"
}];
let arr2 = [{
  name: "Ana Marie",
  status: "married"
  gender: Female
}];

I'm attempting to achieve the following output in JavaScript:

var arr3 = [{name: "Shaina", age: "27"},{name:"Ana Marie Cruz", age: "35",status:"married",gender:Female}];

Answer №1

Here is an example of how you can achieve this:

let arrayOne = [{
  title: "John Doe",
  age: "30"
}, {
  title: "Jane Smith",
  "age": "25"
}];
let arrayTwo = [{
  name: "Jane",
  status: "single",
  gender: 'Female'
}];

let resultArray = arrayOne.map(item => {
 const foundItem = arrayTwo.find(({name}) => item.title.includes(name))
 
 return {
   ...(foundItem || {}),
   ...item
 }
 
})
console.log(resultArray)

Answer №2

const people1 = [
  {
    name: "Shaina",
    age: "27",
  },
  {
    name: "Ana Marie Cruz",
    age: "35",
  },
];

const people2 = [
  {
    name: "Ana Marie",
    status: "married",
    gender: "Female",
  },
];

const mergedData = people1.map((person) => {
  const data = people2.find((p) => person.name.includes(p.name));
  if (!data) return person;
  return {
    ...person,
    ...data,
  };
});

console.log(mergedData);

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