Having issues with the onclick _dopostback function in MVC? It seems like the post

Question

Having issues with the onclick _dopostback function in MVC? It seems like the post

When attempting to execute a postback in ASP.NET MVC after confirming with JavaScript, the following button is used:

<input type="submit" id ="RemoveStatus" value="Remove Status" name="button" onclick="return CheckRemove();"/>

The JavaScript code for the CheckRemove() function is as follows:

var button1 = document.getElementById("RemoveStatus");

     if (confirm("Are you sure you want to remove status?") == true) 
                {
                    button1.disabled = true;
                    button1.value = "Removing status...";
                    __doPostBack('RemoveStatus', '');
                    return true;


                }
                else 
                {
                    return false;
                }

Despite setting the id and populating the button1 in debug, an "object expected" error is encountered at the __doPostBack function. I have attempted passing button1.id and button1 as arguments to __doPostBack, but the postback does not occur and the error persists. Any insights on resolving this issue would be greatly appreciated.

javascript asp.net asp.net-mvc postback dopostback

Answer 1

Answer №1

In MVC, postbacks are not used as they were in webforms. Instead, you can achieve the same effect by using nameoftheform.submit();.

For more information, visit:

To generate an id for the form tag, you can use the following code:

<% using (Html.BeginForm("Create", "Test", FormMethod.Post, new {id="myForm"})) {%>

Then, in your script, you can submit the form using:

document.getElementById('myForm').submit();

If you prefer using jQuery, you can achieve the same result with:

$('#myForm').submit();

Answer 2

In MVC, postbacks are not used as they were in webforms. Instead, you can achieve the same effect by using nameoftheform.submit();.

For more information, visit:

To generate an id for the form tag, you can use the following code:

<% using (Html.BeginForm("Create", "Test", FormMethod.Post, new {id="myForm"})) {%>

Then, in your script, you can submit the form using:

document.getElementById('myForm').submit();

If you prefer using jQuery, you can achieve the same result with:

$('#myForm').submit();

Answer 3

Answer №2

Have you attempted to submit using jQuery in this manner?

$("#RemoveStatus").submit();

This approach proved successful for me personally

Answer 4

Have you attempted to submit using jQuery in this manner?

$("#RemoveStatus").submit();

This approach proved successful for me personally

Answer 5

Answer №3

Utilize the powerful Jquery submit function.

For a helpful example, you can refer to this resource. Remember to include return:false; to prevent the form from being posted twice: once via jQuery and once from the button call within the form.

Another advantage is that in your MVC Action (in your controller), you can directly access your Model if you have one. By binding your model to text fields, you automatically receive an updated model without needing to parse the form collection.

This content contains code snippets from a personal project:

On a page object stored in the database.

When setting up the view, I opt for a strongly typed approach with the page object, leading to:

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<LIB.Data.Page>" %>

I establish the connection between my model and textboxes:

<legend>Fields</legend>
<div class="editor-field">
    <%=Html.TextBoxFor(model => model.Title)%>
</div>

In the controller, the following actions are taken:

[HttpPost]
    [ValidateInput(false)]
    public ActionResult Create(Page model, FormCollection collection)
    {
        PageService.AddPage((string)Session["lang"], model);
        return RedirectToAction("Index", new { menuGuid = model.MenuGuid });
    }

The data inputs from the text fields are automatically bound to the model, which is then retrieved in the controller and stored.

Answer 6

Utilize the powerful Jquery submit function.

For a helpful example, you can refer to this resource. Remember to include return:false; to prevent the form from being posted twice: once via jQuery and once from the button call within the form.

Another advantage is that in your MVC Action (in your controller), you can directly access your Model if you have one. By binding your model to text fields, you automatically receive an updated model without needing to parse the form collection.

This content contains code snippets from a personal project:

On a page object stored in the database.

When setting up the view, I opt for a strongly typed approach with the page object, leading to:

<%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<LIB.Data.Page>" %>

I establish the connection between my model and textboxes:

<legend>Fields</legend>
<div class="editor-field">
    <%=Html.TextBoxFor(model => model.Title)%>
</div>

In the controller, the following actions are taken:

[HttpPost]
    [ValidateInput(false)]
    public ActionResult Create(Page model, FormCollection collection)
    {
        PageService.AddPage((string)Session["lang"], model);
        return RedirectToAction("Index", new { menuGuid = model.MenuGuid });
    }

The data inputs from the text fields are automatically bound to the model, which is then retrieved in the controller and stored.

Having issues with the onclick _dopostback function in MVC? It seems like the post

Answer №1

Answer №2

Answer №3

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