Guidelines on separating data using square brackets when defining parameters in JSON

Question

Guidelines on separating data using square brackets when defining parameters in JSON

Currently, I am transferring data from a JavaScript file to a handler that retrieves results from a stored procedure. The parameter I need to pass is in the format ID = abc[123], but I only want to pass 123 as the value to the stored procedure. Below is how I am declaring the parameter in JavaScript:

var parameters = JSON.stringify({
    "ID": JSON.stringify(EditedID).replace(/]|[[]/g, '')
     });

However, I am encountering an error stating "invalid ID". Can someone please assist me with this issue?

javascript json

Answer 1

Answer №1

At the moment, you are removing the regex and replacing it with nothing, which will result in 'abc123'. What you really want is to extract the string inside the brackets. You can achieve this using the code below:

var EditedID = "abc[123]"
var regex = /\[([^\[\]]*)\]/
var result = ""
match = JSON.stringify(EditedID).match(regex)
if (match != null) {
    result = match[1]
}

"result = match[1]" signifies that the value within the brackets will be assigned to result. If you prefer including the brackets, use match[0].

I'm assuming your EditedID is an object and needs to be converted into a String using the method "JSON.stringify". If EditedID is already a String, simply adjust the match value for simplicity.

match = EditedID.match(regex)

If there is no match, the code will skip the if condition and result will remain an empty String.

Answer 2

At the moment, you are removing the regex and replacing it with nothing, which will result in 'abc123'. What you really want is to extract the string inside the brackets. You can achieve this using the code below:

var EditedID = "abc[123]"
var regex = /\[([^\[\]]*)\]/
var result = ""
match = JSON.stringify(EditedID).match(regex)
if (match != null) {
    result = match[1]
}

"result = match[1]" signifies that the value within the brackets will be assigned to result. If you prefer including the brackets, use match[0].

I'm assuming your EditedID is an object and needs to be converted into a String using the method "JSON.stringify". If EditedID is already a String, simply adjust the match value for simplicity.

match = EditedID.match(regex)

If there is no match, the code will skip the if condition and result will remain an empty String.

Guidelines on separating data using square brackets when defining parameters in JSON

Answer №1

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