Guide to pulling out letters and digits from an array and converting them into a string with the help of a function in javascript

Question

Guide to pulling out letters and digits from an array and converting them into a string with the help of a function in javascript

My task involves passing an array of characters to a function, extracting only letters and numbers from the array, converting those characters into a string, and returning the string. However, I am facing an issue as my function is not returning the correct value. For example, if the input array was ['A','-','5','/','v','$,'f','4','%','2','3',''], the expected output should be the string 'A5vf423'.

I am debating whether I need to declare arrayInput or str, but I suspect that the problem lies in how I am transferring the characters from the vector to the string.

var high = function(arrayInput) {

  var str = '';

  for (var i = 0; i < arrayInput; i++) {

    if (arrayInput[i] >= 'a' && arrayInput[i] <= 'a' &&
      arrayInput[i] >= 'A' && arrayInput[i] <= 'Z'&&
      arrayInput[i] >= '0' && arrayInput[i] <= '9') {

      str = arrayInput[i].join('');
    }
    return str
  };
}

EDIT: Solution:

return arrayName.filter(character => /^[a-zA-Z0-9]/.test(character)).join("")

javascript arrays string character

Answer 1

Answer №1

You can implement regex to determine whether a character is a letter or a number:

By using filter, you can iterate through each element and identify if it is a letter or a number, returning only those elements that meet the criteria.

Regex:

[a-z|0-9] : includes any characters between a-z or 0-9
/i : case insensitive matching

const arr = ["A", "/", "r", "6", ".", "a"];

function getString(arr) {
  return arr.filter(ch => ch.match(/[a-z|0-9]/i)).join("")
}

console.log(getString(arr))

Answer 2

You can implement regex to determine whether a character is a letter or a number:

By using filter, you can iterate through each element and identify if it is a letter or a number, returning only those elements that meet the criteria.

Regex:

[a-z|0-9] : includes any characters between a-z or 0-9
/i : case insensitive matching

const arr = ["A", "/", "r", "6", ".", "a"];

function getString(arr) {
  return arr.filter(ch => ch.match(/[a-z|0-9]/i)).join("")
}

console.log(getString(arr))

Answer 3

Answer №2

Modify your conditional statement:

(arrayInput[i]>='a'&&arrayInput[i]<='z'||arrayInput[i]>='A'&&arrayInput[i]<='Z'||arrayInput[i]>='0'&&arrayInput[i]<='9')

The condition above does not require parentheses due to operator precedence.

Answer 4

Modify your conditional statement:

(arrayInput[i]>='a'&&arrayInput[i]<='z'||arrayInput[i]>='A'&&arrayInput[i]<='Z'||arrayInput[i]>='0'&&arrayInput[i]<='9')

The condition above does not require parentheses due to operator precedence.

Answer 5

Answer №3

const filterCharacters = (inputArray) => {

  let filteredString = '';

  for (let index = 0; index < inputArray.length; index++) {
    if ((inputArray[index] >= 'a' && inputArray[index] <= 'z') ||
        (inputArray[index] >= 'A' && inputArray[index] <= 'Z') ||
        (inputArray[index] >= '0' && inputArray[index] <= '9')) {

      filteredString += inputArray[index];
    }
  }

  return filteredString;
}

Answer 6

const filterCharacters = (inputArray) => {

  let filteredString = '';

  for (let index = 0; index < inputArray.length; index++) {
    if ((inputArray[index] >= 'a' && inputArray[index] <= 'z') ||
        (inputArray[index] >= 'A' && inputArray[index] <= 'Z') ||
        (inputArray[index] >= '0' && inputArray[index] <= '9')) {

      filteredString += inputArray[index];
    }
  }

  return filteredString;
}

Guide to pulling out letters and digits from an array and converting them into a string with the help of a function in javascript

Answer №1

Answer №2

Answer №3

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