Guide on displaying an element depending on the chosen value from a dropdown list using AngularJS

Below is the HTML code I am working on:

<select ng-model='selectedtype' ng-options='item.tagname for item in types.name'>
    <option value="">select type</option> 
</select>
<p ng-show = 'selectedtype.tagname in {{primitives}}'> 
    <br>value of the field : <input ng-model='blockvalue' type='text' name='blockvalue'> <br>
</p>

I want to display the paragraph with the block value input only when certain types are selected.

The following array contains the types that should trigger the display:

$scope.primitives =["gco:CharacterString","Real","Integer","Decimal","Url","gco:Date","gco:DateTime","gco:Measure"];

Here is an example of the types that can be selected:

{
    "tagname": "gmd:abstract",
    "#text": "Abstract"
},
{
    "tagname": "gco:CharacterString",
    "#text": "Primitive type"
}

I understand that the current expression may not work, but I am struggling to find a solution.

Answer №1

When dealing with an array of primitives, you can simply utilize this method:

<p ng-show = 'primitives.indexOf(selectedtype.tagname) != -1'> 
    <br>Field value: <input ng-model='blockvalue' type='text' name='blockvalue'> <br>
</p>

Answer №2

Employ primitives.indexOf(selectedtype.tagname) !== -1 within ng-show condition

<span ng-show='primitives.indexOf(selectedtype.tagname) !== -1'>

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