I want to generate a random 8-digit number ranging from 0 to 7, excluding the numbers 8 and 9. Here is what I have tried so far, but I'm unable to exclude the numbers 8 and 9:
var b = Math.floor(Math.random()*90000000) + 10000000;
console.log(b)
Is there a quicker way to generate a random 8-digit number excluding certain numbers, or do I really need to generate each digit one by one and add them up until I reach 8 digits?
To change into octal form (comprising of digits 0-7) and cut down to the preferred size:
num.toString(8).slice(0, 8)
To generate a random number in octal system, first find the maximum number that can be represented with 8 digits in octal. Then, use the decimal system to generate a random number within that range and convert it back to octal.
var maxOctal = parseInt(100000000, 8);
console.log(('0000000' + Math.floor(Math.random() * maxOctal).toString(8)).slice(-8));If you're in need of an 8-digit number in base 8, you're essentially searching for a decimal number between 8^7 and 8^8-1, which can then be converted to base 8. The following code should help you achieve this:
// Setting the minimum and maximum values
var vmin = Math.pow(8,7);
var vmax = Math.pow(8,8)-1;
// Generating a random number within the specified range
var dec = Math.floor(Math.random()*(vmax-vmin))+vmin;
// Converting the number to base 8
console.log(dec.toString(8));Maybe you're interested in a variation of this code snippet:
let randomNumber = Math.floor(Math.random()*10);
console.log(randomNumber);
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