How can I filter an object to return a new object containing elements with the same values?
For example:
allValues = {"id1": 3, "id2": 4, "id3": 3}
The desired output is:
filteredValues = {"id1": 3, "id3": 3}
This is because the keys "id1" and "id3" have the same value.
The resulting object will only contain 3 keys and values. If no values are shared, an empty object should be returned. Any solutions?
With the consistent presence of 3 data in the object,
I find it more convenient to manually compare them.
const IsSame = (...data) => {
return data.every((value, _, array) => value === array[0])
}
const Process = (raw) => {
const keys = Object.keys(raw)
const values = Object.values(raw)
const value = values[0]
if (IsSame(values[0], values[1], values[2])) return {
[keys[0]]: value,
[keys[1]]: value,
[keys[2]]: value,
}
if (IsSame(values[0], values[1])) return {
[keys[0]]: value,
[keys[1]]: value,
}
if (IsSame(values[0], values[2])) return {
[keys[0]]: value,
[keys[2]]: value,
}
if (IsSame(values[1], values[2])) return {
[keys[1]]: value,
[keys[2]]: value,
}
return {}
}
const raw = {
"id1": 1,
"id2": 0,
"id3": 1
}
const result = Process(raw)
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