Finding the tiniest match within a regex pattern

Looking for a way to match the fourth element in this expression:

var string = [a][1] [b][2] [c][3] [d .-][] [e][4]

The element we're trying to target is [d .-][]. This specific element can contain any character within the first set of brackets, while the second set remains empty. Other elements like [a][1] can contain any character but must have a number inside their second set of brackets.

I attempted using this regex pattern:

string.match(/\\[[^]+]\\[ ]/);

However, it proved to be too greedy in its matching.

If you have any suggestions or solutions, I would greatly appreciate your help.

Answer №1

In my quest to find the fourth element [d .-][] which can consist of any character (letters, numbers, punctuation, etc) within the initial set of brackets while leaving the second set empty

string.match(/\[[^\]]*\]\[\]/)

should get the job done.

Breaking it down,

\[ matches a literal left square bracket,

[^\]]* matches any number of characters except for a right square bracket,

\] matches a literal right square bracket, and

\[\] matches the two-character sequence [], with nothing in between brackets.

To address your inquiry regarding greediness, you can make the greedy match [^]+ non-greedy by adding a question mark: [^]+?. Keep in mind that [^] does not function properly in IE. For matching any UTF-16 code units, I usually use [\s\S], which is slightly more verbose but compatible with all browsers.

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